Answer:
5.09 × 10^-2
Step-by-step explanation:
You have to take the number go to the decimal and move it until you get to the first number and in this case, it is 5 put the decimal there. To write it you have to count the number of times you moved the decimal. when doing this it will always be a number times 10^ the number you moved the decimal.
Answer: 0.79
Step-by-step explanation:
I will suppose that this is not a continuos probability, as the individual probabilites add up to 100%.
If you want to obtain the probability that x ≤ 0, then you need to add the probability for the cases x= 0, x = -1, x = -2 .... etc
This is:
x = 0, p = .16
x = -2, p = .33
x = -3, p = .13
x = -5, p = .17
Then, the probability where x takes a negative value or zero {-5, -3, -2, 0} is:
P = 0.16 + 0.33 + 0.13 + 0.17 = 0.79
Answer:
b. 9/100
Step-by-step explanation:
It helps if you have memorized the cubes of small integers. Of course, the ones needed here are ...
3³ = 27
10³ = 1000
The desired value can be simplified to ...
![\left(-\dfrac{1000}{27}\right)^{-2/3}=\left(-\sqrt[3]{\dfrac{3^3}{10^3}}\right)^2=\dfrac{(-3)^2}{10^2}=\dfrac{9}{100}](https://tex.z-dn.net/?f=%5Cleft%28-%5Cdfrac%7B1000%7D%7B27%7D%5Cright%29%5E%7B-2%2F3%7D%3D%5Cleft%28-%5Csqrt%5B3%5D%7B%5Cdfrac%7B3%5E3%7D%7B10%5E3%7D%7D%5Cright%29%5E2%3D%5Cdfrac%7B%28-3%29%5E2%7D%7B10%5E2%7D%3D%5Cdfrac%7B9%7D%7B100%7D)
Answer: √51
—————————
a^2 + b^2 = c^2
a^2 + 7^2 = 10^2
a^2 + 49 = 100
a^2 = 51
√(a^2) = √51
a = √51
