A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>
Its slope would be:
The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as
The equation of a line is
Hence, the equation is 11x +6y - 80 = 0
Learn more about slopes here:
brainly.com/question/2503591
#SPJ4
Answer:
36
Step-by-step explanation:
56=7-3[4+{8-4(4+5-3)}]
56=7-3[4+{4(4+5-3)}]
56=7-3[4+{16+20-12)}]
56=7-3[4+24]
56=4[28]
56=92
56-56=92-56
36
Answer:
Option C, 30
Step-by-step explanation:
<u>Step 1: Identify how many people spent $200</u>
There was only 30 people that spent $200
Answer: Option C, 30
Answer:
11y-2x= -90
Step-by-step explanation:
for the point (1,-8)
x=1 and y= -8
for the equation,
2x -4y= -11
x= -1/m
m= -1/x
x = -1/ (-11/2 )
m= 2/11
so for the equation,
y-y1= m(x- x1)
y- -8=2/11(x-1)
11(y+8)= 2(x-1)
11y +88= 2x-2
11y-2x= -90
