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3 years ago

Does organisms get rid of waste

Physics

2 answers:

Leviafan [203]3 years ago

5 0

Depends on the organism you are talking about

Strike441 [17]3 years ago

3 0

Bacteria get rid of waste through their semi-permeable membrane by diffusion. The waste is pushed out of the organism in the form of liquid or gas. The waste released by bacteria is usually toxic and is what makes people sick.

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Trong thí nghiệm về giao thoa sóng trên mặt nước gồm hai nguồn kết hợp S1S2 cách nhau 15 cm với dao động với tần số 30Hz. Tốc độ

mojhsa [17]

Answer:

this is a difficult question but I will try to answer it answer for this is 3220 a + b b u s y d l new

6 0

2 years ago

weegy a 7.5kg block is placed on a table. if its bottom surface area is 0.6m2 , how much pressure does the block exert on the ta

Lesechka [4]

The pressure exerted by the block on the table is given by:

$p=\frac{W}{A}$

where W is the weight of the box, and A is the bottom surface area of the box.

The weight of the box is: $W=mg=(7.5 kg)(9.81 m/s^2)=73.6 N$

Substituting into the first equation, we find the pressure:

$p=\frac{W}{A}=\frac{73.6 N}{0.6 m^2}=122.7 Pa$

4 0

3 years ago

The law of conservation of momentum states that the total momentum of interacting objects does not change . This means the total

pickupchik [31]

Answer:

The momentum of an object is equal to the product of its mass and its velocity.

Explanation:

Consider an object of mass $m$ travelling at a velocity $\vec{v}$ . The momentum $\vec{p}$ of this object would be:

$\vec{p} = m \cdot \vec{v}$ .

For the law of conservation of momentum, consider two objects: object $\rm a$ and object $\rm b$ . Assume that these two objects collided with each other.

Let $m_{\rm a}$ and $m_{\rm b}$ denote the mass of the two objects.
Let $\vec{v}_{\rm a}(\text{initial})$ and $\vec{v}_{\rm b}(\text{initial})$ denote the velocity of the two object right before the interaction.
Let $\vec{v}_{\rm a}(\text{final})$ and $\vec{v}_{\rm b}(\text{final})$ denote the velocity of the two objects right after the interaction.

The momentum of the two objects right before the collision would be $m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial})$ and $m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial})$ , respectively.
The momentum of the two objects right after the collision would be $m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final})$ and $m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})$ , respectively.

The sum of the momentum of the two objects would be:

$m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial})$ right before the collision, and
$m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})$ right after the collision.

Assume that the system of these two objects is isolated. By the law of conservation of momentum, the sum of the momentum of these two objects should be the same before and after the collision. That is:

$m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) = m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})$ .

4 0

3 years ago

In a typical lightning strike, 2.0 c flows from cloud to ground in 0.24 ms. what is the current during the strike?

lyudmila [28]

Current = charge/time = (2 c)/(0.00024 sec)= 8,333 Amps !

4 0

3 years ago

Your new motorcycle weighs 2450 N.

Whitepunk [10]

Answer:

Explanation:

The negative only matters reallly if you are dealing with a 2d system. I could even define down as positive and up as negative. However, usually you are taught that down is negative. It really doesn't matter because a force is a force. It is only given a direction relative to another force or vector direction.

5 0

2 years ago