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melamori03 [73]
3 years ago
15

Two movers are pushing a large crate with a force of 60.0 n each. one pushes north, the other east. what is the equilibrant forc

e
Physics
1 answer:
romanna [79]3 years ago
8 0
To get the solution you must need to draw a force triangle. Attach the head of the 60N north force arrow with the tail of the 60N east force arrow. The subsequent is the arrow connecting he tail and head of the two arrows. 
You get a right angled triangle, and the resultant is (60^2 + 60^2) ^0.5 = 84.85 N or 85 N northeast.
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At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 6
Ilia_Sergeevich [38]
Momentum of car

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Formula:  P = mv    

                P = (1,400 Kg)(6.0 m/s)

                P = 8,400 Kg.m/s

Velocity of the rider to have the same momentum as a car.

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V = P/m

V = 8,400 Kg.m/s/100 Kg

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7 0
2 years ago
NASA scientists suggest using rotating cylindrical spacecraft to replicate gravity while in a weightless environment. Consider s
dusya [7]

Answer:

Explanation:

Given

diameter of spacecraft d=148\ m

radius r=74\ m

Force of gravity F_g=mg

where m =mass of object

g=acceleration due to  gravity on earth

Suppose v is the speed at which spacecraft is rotating so a net centripetal  acceleration is acting on spacecraft which is given by

F_c=\frac{mv^2}{r}

F_c=F_g

\frac{mv^2}{r}=mg

\frac{v^2}{r}=g

v=\sqrt{gr}

v=\sqrt{1450.4}

v=38.08\ m/s    

8 0
3 years ago
Tarzan swings on a 31.0 m long vine initially inclined at an angle of 36.0◦ with the vertical. The acceleration of gravity if 9.
Gennadij [26K]

Answer:

v=10.777m/s

Explanation:

Tarzan swing can be thought of as change in potential energy by going from higher location We solve for height of beginning of the swing by using simple cosine equation:

So

31Cos36=25.08\\E_{potential}=mgh\\

ΔE=mg(h₂-h₁)

=m*9.81(31-25.08)\\

The potential energy of Tarzan initial position is converted into kinetic energy of his swing.By using kinetic equation

E_{kinectic}=P_{potential}\\1/2mv^{2}=m*9.81(31.0-25.08)\\(1/2)v^{2}=9.81(31.0-25.08)\\0.5v^{2}=58.07\\v^{2}=58.07/0.5\\v=\sqrt{58.07/0.5}\\ v=10.777m/s    

8 0
3 years ago
Which sphere of Earth is associated with plate tectonics?
Marrrta [24]

When looking at this question, we can easily start by eliminating certain answers. In the selections you've provided, you've shown atmosphere. We can easily eliminate letter A, as that makes absolutely no sense. Moving on, you also eliminate letter B, as that deals with ecosystems and whatnot. And finally, you can eliminate hydrosphere, letter C - as that's not the same. That deals with water, like oceans or rivers.

That leaves you with D) Lithosphere for your answer. The Lithosphere is the rigid part of the earth, the outermost layer, I would say. The crust / mantle. That's why it would be letter D - plate tectonics seem to have relations with the Lithosphere. The lithosphere is affected.

5 0
3 years ago
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Answer:

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