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daser333 [38]
3 years ago
11

Please help me. Urgent!!!

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0
Im pretty sure the answer would be a
zlopas [31]3 years ago
4 0

Answer:

Your answer would be A

The site Math-way is a good tool for this

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Pleasee help x.x 1. Solve the system by elimination-
patriot [66]
Q1. The answer is x = 1, y = 1, z = 0

<span>(i) -2x+2y+3z=0
</span><span>(ii) -2x-y+z=-3 
</span>(iii) <span>2x+3y+3z=5
</span><span>_________
Sum up the first and the third equation:
</span>(i) -2x+2y+3z=0
(iii) 2x+3y+3z=5
_________
5y + 6z = 5

Sum up the second and the third equation:
(ii) -2x-y+z=-3 
(iii) 2x+3y+3z=5
_________
2y + 4z = 2


(iv) 5y + 6z = 5
(v) 2y + 4z = 2
________
Divide the fifth equation by 2
(iv) 5y + 6z = 5
(v) y + 2z = 1
________
Multiple the second equation by -3 and sum the equation
(iv) 5y + 6z = 5
(v) -3y - 6z = -3
________
2y = 2
y = 2/2 = 1


y + 2z = 1
1 + 2z = 1
2z = 1 - 1
2z = 0
z = 0


-2x-y+z=-3
-2x - 1 + 0 = -3
-2x = -3 + 1
-2x = -2
x = -2/-2 = 1



Q2. The answer is x = -37, y = -84, z = -35

<span>(i) x-y-z=-8 
(ii) -4x+4y+5z=7 
(iii) 2x+2z=4
______
</span>Divide the third equation by 2 and rewrite z in the term of x:
(iii) x+z=2
z = 2 - x
______
Substitute z from the third equation and express y in the term of x:
<span>x-y-(2-x)=-8 
x - y - 2 + x = 8
2x - y = 10
y = 2x - 10
______
Substitute z from the third equation and y from the first equation into the second equation:
</span><span>-4x + 4y + 5z = 7 
-4x + 4(2x - 10) + 5(2 - x) = 7
-4x + 8x - 40 + 10 - 5x = 7
-x -30 = 7
-x = 30 + 7
x = -37
y = 2x - 10 = 2*(-37) - 10 = -74 - 10 = -84
z = 2 - x = 2 - 37 = -35</span>
8 0
3 years ago
In the figure above, PQRS is a circle. If PQT and SRT<br>are straight lines, find the value of x.
Elena L [17]

Given:

PQRS is a circle, PQT and SRT  are straight lines.

To find:

The value of x.

Solution:

Since PQRS is a circle, PQT and SRT  are straight lines, therefore, PQRS isa cyclic quadrilateral.

We know that, sum of opposite angles of a cyclic quadrilateral is 180 degrees.

m\angle SPQ+m\angle QRS=180^\circ

81^\circ+m\angle QRS=180^\circ

m\angle QRS=180^\circ-81^\circ

m\angle QRS=99^\circ

Now, SRT  is a straight line.

m\angle QRT+m\angle QRS=180^\circ             (Linear pair)

m\angle QRT+99^\circ=180^\circ

m\angle QRT=180^\circ-99^\circ

m\angle QRT=81^\circ               ...(i)

According to the Exterior angle theorem, in a triangle the measure of an exterior angle is equal the sum of the opposite interior angles.

Using exterior angle theorem in triangle QRT, we get

m\angle PQR=m\angle QRT+m\angle QTR

x=81^\circ+22^\circ

x=103^\circ

Therefore, the value of x is 103 degrees.

4 0
3 years ago
In AWXY, mW<br> Find mZX<br> (2x – 12), m_X = (2x + 17), and m_Y = (9x-7)<br> Find m
sladkih [1.3K]

Answer:

45

Step-by-step explanation:

The sum of interior angles in a triangle is equal to 180

2x - 12 + 2x + 17 + 9x - 7 = 180 add like terms

13x - 2 = 180 add 2 to both sides

13x = 182 divide both side by 13

x = 14

m<X = 2x + 17 replace x with 14

2*14 + 17 = 45

5 0
2 years ago
Solve using the multiplication principle 4 x = 52
IrinaVladis [17]
The value of x is 13
4 0
2 years ago
Read 2 more answers
Simplify √(49^8) ? a) 7√(5a^8) b) 7a^4 c)a√(24.5) d) 7a^8 please help as soon as possible.
WITCHER [35]
\bf \sqrt{49^8}~~&#10;\begin{cases}&#10;49=7\cdot 7\\&#10;\qquad 7^2&#10;\end{cases}\implies \sqrt{(7^2)^8}\implies \sqrt{(7^8)^2}\implies 7^8\\\\\\ 5764801
5 0
3 years ago
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