The answer is infinitely many solutions because 0 = 0.
If you don't seem to see where I got 0 = 0, look at the equation,
4b – 4b = 0
first lets do the math on the left side.
4b - 4b is equal to 0.
so lets put 0 on the left side, now lets look at the equation all together,
0 = 0,
and this means that it has infinitely many solutions.
The reason why it is not no solution because no solution means when there are no answers to the equation. For example, the solution is not true, such as the equation 24 ≠ 29. This is a no solution equation. One solution can be 4x = 20, as x = 5, concluding it being one solutions.
Answer:
its rational
Step-by-step explanation:
:)
Answer: 48 tickets
Step-by-step explanation:
Since the expression that gives the number of tickets a player wins if he shoots the ball in the hoop t times is expressed as 3t.
Therefore, the number of tickets that a player wins if he shoots the ball in the hoop 16 times will be:
= 3t
where,
t = 16
Therefore, 3t = 3 × 16 = 48
The player wins 48 tickets.
Remember the rules of PEMDAS
1. First you want to evaluate the parentheses. (4-1) = 3
2. Square:
3^2 = 9
3. Multiply: 9*2 = 18
Your answer is C
Answer:
1) Decimal 
2) Binary 
3) Octal 
4) Hexadecimal 
Step-by-step explanation:
Given : Integer is 25
To find : Represent integer in decimal, binary, octal, and hexadecimal formats.
Solution :
1) Integer into decimal - To convert into decimal the base goes to 10.
So, 
2) Integer into binary - To convert into binary the base goes to 2, it form in 0 and 1 and we divide integer by 2.
Divide 25 by 2 and note down the remainders.
2 | 25
2 | 12 R=1 ←
2 | 6 R=0 ↑
2 | 3 R=0 ↑
2 | 1 → R=1 ↑
So, 
3) Integer into octal - To convert into octal the base goes to 8 and we divide integer by 8.
Divide 25 by 8 and note down the remainders.
8 | 25
| 3 → R=1
So, 
4) Integer into hexadecimal - To convert into hexadecimal the base goes to 16 and we divide integer by 16.
Divide 25 by 16 and note down the remainders.
16 | 25
| 1 → R=9
So, 