Answer:
D. When the dense, positive alpha particle passes close to a positive nucleus of gold, the alpha particle repels and hits the screen at point X.
Explanation:
To solve this problem it is necessary to apply the concepts related to Period in a spring, elastic potential energy and energy in simple harmonic movement.
From the definition we know that the period can be expressed as
Where
m= Mass
k = Spring constant
Our values are given as
m = 16.6Kg
K = 2470N/m
Therefore the period would be
PART A) The frequency is the inverse of the period therefore
PART B) Elastic potential energy depends on compression and elasticity therefore
PART C) Kinetic energy depends on mass and speed therefore
PART D) As energy is conserved, the total energy is equivalent to the dual ratio of the elasticity constant and the amplitude, mathematically,
Therefore the motion's amplitude is 1.07m
Answer:
A body moving on a circular path with constant speed that is undergoing a uniform circular motion has variable velocity. The direction of velocity changes each moment and hence the velocity is not constant.
Explanation:
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