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Mademuasel [1]
2 years ago
14

If a 1.00 kg body has an acceleration of 2.44 m/s2 at 53° to the positive direction of the x axis, then what are (a) the x comp

onent and (b) the y component of the net force on it, and (c) what is the net force in unit-vector notation?
Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
6 0

(a) Fx = 1.464 N

(b) Fy = 1.952 N

(c) F(x, y) = 1.464 i + 1.952 j

Given

Mass = 1kg

Acceleration = 2.44 m/s2

Angle with positive X axis = 53°

As we know

F = ma

By substituting value

F= 1×2.44 N

F= 2.44 N

(a)   Component of force in X direction

Fx = F Cosθ

Fx = 2.44 Cos(53°)

Fx = 2.44 × 0.60 = 1.464 N

(b) Component of force in Y direction

Fy = F Sinθ

Fy = 2.44 Sin(53°) = 2.44 × 0.80 = 1.952 N

(c) Net force in vector notation

F(x, y) = 1.464 i + 1.952 j

Thus we got net force.

#SPJ4

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A piece of driftwood moves up and down as water waves pass beneath it. However, it does not move toward the shore with the waves
KIM [24]

Answer:A piece of driftwood moves up and down as water waves pass beneath it. However, it does not move toward the shore with the waves. What does this demonstrate about the propagation of waves through a medium?

A) Waves transmit energy but not matter as they progress through a medium.

B) Waves transmit matter but not energy as they progress through a medium.

C) Waves do not transmit matter or energy as they progress through a medium.

D) Waves transmit energy as well as matter as they progress through a medium.

Explanation:

A piece of driftwood moves up and down as water waves pass beneath it. However, it does not move toward the shore with the waves. What does this demonstrate about the propagation of waves through a medium?

A) Waves transmit energy but not matter as they progress through a medium.

B) Waves transmit matter but not energy as they progress through a medium.

C) Waves do not transmit matter or energy as they progress through a medium.

D) Waves transmit energy as well as matter as they progress through a medium.

4 0
3 years ago
Two protons are released from rest when they are 0.750 {\rm nm} apart.
Alex787 [66]

Explanation:

Given:

m = 1.673 × 10^-27 kg

Q = q = 1.602 × 10^-19 C

r = 0.75 nm

= 0.75 × 10^-9 m

A.

Energy, U = (kQq)/r

Ut = 1/2 mv^2 + 1/2 mv^2

1.673 × 10^-27 × v^2 = (8.99 × 10^9 × (1.602 × 10^-19)^2)/0.75 × 10^-9

v = 1.356 × 10^4 m/s

B.

F = (kQq)/r^2

F = m × a

1.673 × 10^-27 × a = ((8.99 × 10^9 × (1.602 × 10-19)^2)/(0.075 × 10^-9)^2

a = 2.45 × 10^17 m/s^2.

4 0
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Why does changing the shape of an object have no effect on the density?
iren [92.7K]
Because the object is still made of the same material 
Density is not affected by the weight and shape of an object its affected by how concentrated the atoms are in a given volume 
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A solid disk has a mass of 162 kg and a radius of 1.30m. This
RideAnS [48]

Answer:

754.3 m

Explanation:

The moment of inertia of the solid disk:

I = mR^2/2

Where m is the disk mass and R is the radius of the disk.

I = 162*1.3^2/2 = 136.89 kgm^2

The angular kinetic energy of the disk is then:

E_k = I\omega^2/2 = 136.89 * 18^2/2 = 22176.18 J

By law of energy conservation, this energy is converted to potential energy to pick up the 3kg block

let g = 9.8 m/s2

E_p = m_bgh = 22176.18 J

where m_b = 3 kg is the mass of block

3*9.8h = 22176.18

h = \frac{22176.18}{3*9.8} = 754.3 m

8 0
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This is known as work
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