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Semenov [28]
4 years ago
13

Which device converts electrical energy into kinetic energy?

Physics
2 answers:
andriy [413]4 years ago
4 0
<h3><u>Answer;</u></h3>

<em>Electric motor</em>

<h3><u>Explanation;</u></h3>
  • <em><u>Energy</u></em> is the ability to do work. According to the law of conservation of energy,<em><u> energy can not be created nor destroyed but can be changed from one form to another</u></em>.
  • Changing energy from one form to another is done by devices we call <em><u>transducers. These are elements that convert energy from one form to another.</u></em>
  • In this case, electrical motor is an example of a transducer that converts electrical energy to kinetic energy. <em><u>Electrical energy is supplied to a the motor which converts it to rotational energy or mechanical energy then to kinetic energy.</u></em>
juin [17]4 years ago
3 0

Answer:

<h2>B)Electric motor</h2>

Explanation:

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A 25 kg circular disk has a diameter of 2.5 feet and a thickness of 2.5 cm. Find the density of the disk in kg/m3. Next, find th
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Assume that \rm g= 9.81\; N\cdot kg^{-1}; \rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}.

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Convert the dimensions of this disk to SI units:

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\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m.

Volume of this disk:

V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}.

Density of this disk:

\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}.

\rho(\text{disk}) >\rho(\text{water}) indicates that the disk will sink when placed in water.

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W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N.

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately \rm 0.0114009\; m^{3} of water. The buoyant force on the disk will be:

\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}.

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

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