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stepan [7]
3 years ago
11

Hormones produced by the anterior lobe of the pituitary gland that regulate the male and female reproductive organs are collecti

vely called
Biology
1 answer:
Romashka [77]3 years ago
3 0

Answer:

Gonadotrophin

Explanation:

*GONADOTROPHINS:These are *hormones produced by the anterior lobe of the pituitary gland that regulate the male and female reproductive organ*. The two Gonadotrophins are *Follicle stimulating hormone(FSH) and Luteinising hormone(LH)*. Both are glycoproteins.

*Follicle stimulating hormone stimulates spermatogenesis by stimulating the sertoli cells to complete the development of spermatozoa from spermatids*.

*Luteinising hormone stimulates the synthesis of the hormone "testosterone" by the leydig (interstitial cells) of the testis*. Testosterone is a steroid hormone and is made from cholesterol, It stimulates growth and development of the germinal epithelial cells (spermatogonia) to form sperms,and also works with follicle stimulating hormone to stimulate sertoli cells.

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D. Evaluate

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The team of ecologists failed to implement the evaluation stage of adaptive management approach as the didn't compare various possible methods that could be used for the managemenr process and evaluation refers to analysis of completed or ongoing activities related to the topic in consideration to determine the management effectiveness and efficiency. Since they forgot to evaluate the various possible methods, evaluation is the missed approach.

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8 0
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How does natural selection differ from selective breeding?
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Answer:

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Calculate the volume of 1 M NaOH needed to prepare 12.0 mL of a 0.10-M solution. Prepare this solution. (Refer to the Dilutions
Lapatulllka [165]

Answer:

1.2 mL

Explanation:

<em>This is a problem of simple dilution. The dilution principle simply agrees that the number of moles before dilution must be equal to the number of moles after dilution.</em>

Recall that: number of moles = mass/molar mass or molarity x volume.

Hence, for the dilution principle:

              initial molarity x initial volume = final molarity x final volume.

In this case, initial molarity of NaOH = 1 M, initial volume = ?, final molarity = 0.1 M, final volume = 12.0 mL.

Initial volume = final molarity x final volume/initial molarity

                       = 0.1 x 12/1 = 1.2 mL

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