All categories

3 years ago

❗️5 points❗️ state the slope of the line. A. -2 B. 0 C. 1 D. undefined

Mathematics

1 answer:

Oxana [17]3 years ago

3 0

Answer:

B. 0

Step-by-step explanation:

The slope of a straight horizontal line is always equal to 0.

To support the above statement, we can show working out:

m = slope of the line

m = ( y1 - y2 ) / ( x1 - x2 )

Two points on line = ( 0 , - 2 ) , ( 1 , - 2 )

y1 = - 2

y2 = - 2

x1 = 0

x2 = 1

m = [ ( - 2 ) - ( - 2 ) ] / [ ( 0 ) - ( 1 ) ]

m = ( - 2 + 2 ) / ( 0 - 1 )

m = 0 / - 1

m = 0

The y values on a horizontal line will always be the same. When calculating the subtraction of y values in the numerator of the formula for the slope of a line, a number subtracted by itself will always equal to 0. 0 divided by any number will always equal to 0. Hence, the slope of a straight horizontal line will always equal to 0.

You might be interested in

Nancy buys 15 m of ribbon. Her sister buys 6 m less ribbon but pays twice as much per metre. Together they pay R66. What is the

Katarina [22]

Answer: 44/9 ----> 22/9

I hope this helps you

4 0

3 years ago

Please help I’m in the middle of a testtt!

hichkok12 [17]

Answer:

first option

Step-by-step explanation:

5 0

3 years ago

Please help. Also it’s a picture

kiruha [24]

<h3>Answer: $580.38 (Choice B)</h3>

===================================

Work Shown:

A = P*(1+r/n)^(n*t)

A = 500*(1+0.05/4)^(4*3)

A = 580.3772588615

A = 580.38

4 0

3 years ago

A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(

ratelena [41]

Answer:

The average rate of change of f(t) from t = 3 seconds to t = 5 seconds is -80 feet per second.

Step-by-step explanation:

The function that models the height of the ball is:

$f(t)=-16t^2+48t=160$

At t=3, $f(3)=-16(3)^2+48(3)+160=160$

At t=5, $f(5)=-16(5)^2+48(5)+160=0$

The average rate of change is simply the slope of the secant line connecting.

$(3,f(3))$ and $(5,f(5))$ .

The average rate of change

$=\frac{f(3)-f(5)}{3-5}$

$=\frac{160-0}{-2}$

$=-80fts^{-1}$

5 0

4 years ago

Given GHI G (4,-3), H (-4,2), and I (2,4), find the perpendicular bisector of HI in standard form.

Olin [163]

Answer:

$3x+y=0$

Step-by-step explanation:

step 1

Find the slope of segment HI

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

H (-4,2), and I (2,4)

substitute the given points

$m=\frac{4-2}{2+4}$

$m=\frac{2}{6}$

simplify

$m=\frac{1}{3}$

step 2

Find the slope of the perpendicular line to segment HI

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=\frac{1}{3}$

$m_2=-3$

step 3

Find the midpoint segment HI

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

H (-4,2), and I (2,4)

substitute

$M(\frac{-4+2}{2},\frac{2+4}{2})$

$M(-1,3)$

step 4

we know that

The perpendicular bisector of HI is a line perpendicular to HI that passes though the midpoint of HI

Find the equation of the perpendicular bisector of HI in point slope form

$y-y1=m(x-x1)$

we have

$m=-3$

$M(-1,3)$

substitute

$y-3=-3(x+1)$

step 5

Convert to slope intercept form

$y=mx+b$

Isolate the variable y

$y-3=-3x-3$

$y=-3x-3+3$

$y=-3x$

step 6

Convert to standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

$y=-3x$

Adds 3x both sides

$3x+y=0$

see the attached figure to better understand the problem

3 0

4 years ago