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serious [3.7K]
2 years ago
12

Help please I’m just not good at this and. Get really confused when putting things in standard form. Use two points on the line

to find the equation of the line in standar form

Mathematics
1 answer:
frez [133]2 years ago
7 0

Answer:

From the graph, the slope is -4/5 and the y-intercept is 4 so the slope-intercept equation is y = -4/5x + 4. To convert to standard form we'll do:

y = -4/5x + 4

5y = -4x + 20

4x + 5y = 20

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An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
2 years ago
Select all the relationships that demonstrate a positive association between veriables (multiple choice)
Gnom [1K]

Answer:

a

Step-by-step explanation:

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4 0
2 years ago
&lt;1 and &lt;2 are supplementary angles. The measure of &lt;1 is 87º. The measure of &lt;2 is 15x + 18º.
Kay [80]

Answer: x= 5

Step-by-step explanation: If angles 1 and 2 are supplementary, that means they add up to 180. So if angle 1 is 87, angle 2 has to be 180-87=93. Then the equation would be 15x+18=93. Subtract 18 on both sides. 15x=75. Divide by 15 and your answer is 5.

6 0
2 years ago
Gabrielle uses 7.6 pints of blue paint and white paint to paint her bedroom walls. 1 4 of this amount is blue paint, and the res
zysi [14]

Answer:

1.9

Step-by-step explanation:

Gabrielle uses 7.6 pints of blue and white paint to paint her bedroom

1/4 of the paint is blue paint

Therefore the amount of white paint she used to paint her bedroom can he calculated as follows

= 1/4

= 0.25×100

= 25%

25/100×7.6

= 2.5 × 7.6

= 1.9

Hence 1.9 pints of white paint was used to paint the room

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3 years ago
How do I solve all this
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