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4 years ago

The general kinematic equations of motion for vertical displacement can also be simplified significantly. Write the simplified

Physics

1 answer:

Setler [38]4 years ago

4 0

Answer:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

Explanation:

The general kinematic equation for horizontal displacement is gives as:

Δx = v₀t + (1/2)at²

Where

Δx = change in the x direction

v₀ = initial velocity

t = time

a = acceleration

If the body is vertically instead of horizontally, Δx is changed to Δy

Δy = v₀t + (1/2)at²

For a vertical moving body, the acceleration it experiences is the gravitational accerelation of the earth 'g'

So the equation becomes:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

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If a car with a mass of 1,200 kg traveling westward at 30 m/s is

forsale [732]

The net force acting on the car is equal to -12000 Newton.

<u>Given the following data:</u>

Mass = 1,200 kg

Initial velocity = 30 m/s.

Final velocity = 0 m/s (since the car came to a stop).

Time = 3 seconds.

To determine the net force acting on the car:

<h3>How to calculate the net force.</h3>

Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:

$F = \frac{m(v\;-\;u)}{t}$

<u>Where:</u>

m is the mass.

t is the time.

u is the initial velocity.

u is the final velocity.

Substituting the given parameters into the formula, we have;

$F = \frac{1200 \times (0\;-\;30)}{3}\\\\F = \frac{1200 \times (-30)}{3}\\\\F = \frac{-36000 }{3}$

Net force = -12000 Newton.

Read more on net force here: brainly.com/question/1121817

5 0

2 years ago

A cylinder measuring wide and high is filled with gas. The piston is pushed down with a steady force measured to be . Calculate

jekas [21]

Explanation:

Let us assume that the given cylinder is 2.6 cm wide and its height is 3.1 cm. And, when piston is pushed down then the steady force is equal to 15 N.

Now, radius of the cylinder will be as follows.

r = $\frac{diameter}{2}$

= $\frac{2.6 cm}{2}$

= 1.3 cm

or, = 0.013 m (as 1 m = 100 cm)

As, area of cylinder = $\pi \times r^{2}$

= $3.414 \times (0.013 m)^{2}$

= $5.77 \times 10^{-4} m^{2}$

Relation between pressure and force is as follows.

Pressure = $\frac{Force}{Area}$

= $\frac{15 N}{5.77 \times 10^{-4} m^{2}}$

= 25996 $N/m^{2}$

Since, 1 $N/m^{2}$ = 1 Pa (as 1 kPa = 1000 Pa)

Therefore, P = 25996 $N/m^{2}$

= 25.99 kPa

= 26 kPa (approx)

Thus, we can conclude that pressure of the gas inside the cylinder is 26 kPa.

7 0

3 years ago

Two charges, qA and qB, are separated by a distance, d, and exert a force, F, on each other. Analyze Coulomb's law and answer th

maria [59]

Answer: a. F doubled

b. F reduced by one-quarter i.e

1/4*(F)

c. 1/9*(F)

d. F increased by a factor of 4 i.e 4*F

e. F reduces 3/4*(F)

Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is

F = k*(qA*qB)/d²

a. If qA is doubled therefore the force is doubled since they are directly proportional.

b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4

Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.

c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9

d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4

e. If qA is tripled that is multiplied by 3. F would be multiplied by 3 also, if at the same time d is doubled (2*d)²= 4*d² . Force would be divided by 4 at same time. So we have,

3/4*F

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4 years ago

How much work is required for a 74 kg sprinter to accelerate from rest to 2.2 m/s?

My name is Ann [436]

Answer:

179.1 kg

Explanation:

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2 years ago

Read 2 more answers

Compute the work (in joules) required to compress a spring 3 cm

faust18 [17]

Answer:

7×160=1120kj so,1120kj=1.12j.

Explanation:

Energy is equal to force times distance,so we add all the distance and we multiply them with the total force of the spring to get the answer. However, the answer is in kilojoules so we have to change it in to joules by dividing the answer into joules by 1000..

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3 years ago