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Orlov [11]
4 years ago
7

The general kinematic equations of motion for vertical displacement can also be simplified significantly. Write the simplified

Physics
1 answer:
Setler [38]4 years ago
4 0

Answer:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

Explanation:

The general kinematic equation for horizontal displacement is gives as:

Δx = v₀t + (1/2)at²

Where

Δx = change in the x direction

v₀ = initial velocity

t = time

a = acceleration

If the body is vertically instead of horizontally, Δx is changed to Δy

Δy = v₀t + (1/2)at²

For a vertical moving body, the acceleration it experiences is the gravitational accerelation of the earth 'g'

So the equation becomes:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

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The mass of the rider 1 is 4 g.

<h3>The use of a rider in mass measurement</h3>

Rider is a metallic wire piece which is of certain mass and can be bent . It can move the beam of the Paul Bunge Balance.

The riders are the sliding pointers positioned on top of the beams to show the pan and beam weight in grams.

<h3>Mass of the rider 1</h3>

The mass of the rider 1 is obtained by subtracting mass of riders as show below.

mass of rider 1 = mass of object - (mass of rider 2 + mass of rider 3)

mass of rider 1 = 694 g  - (600 g + 90 g)

mass of rider 1 = 694 g - 690 g

mass of rider 1 = 4 g

Thus, the mass of the rider 1 is 4 g.

Learn more about use of riders in mass measurement here: brainly.com/question/1747339

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A car travelled a distance of 200 m with initial velocity of 216 km/hr. Calculate the acceleration
pogonyaev

Answer:

a = 16\ m/s^2

Explanation:

When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:

v_f^2=v_o^2+2ax

Where:

vf = final velocity

vo = initial velocity

a = acceleration

x = distance

Solving for a:

\displaystyle a=\frac{v_f^2-v_o^2}{2x}

The car travels a distance of x=200 m and the velocities are:

vo = 216 Km/h

vf = 360 Km/h

Both velocities must be converted to meters by seconds.

vo = 216 Km/h *1000/3600 = 60 m/s

vf = 360 Km/h *1000/3600 = 100 m/s

The acceleration is:

\displaystyle a=\frac{100^2-60^2}{2*200}

\displaystyle a=\frac{10000-3600}{400}

\displaystyle a=\frac{6400}{400}

\mathbf{a = 16\ m/s^2}

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3 years ago
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