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2 years ago

Explain how you can improve the accuracy of a measurement.

Physics

2 answers:

yKpoI14uk [10]2 years ago

8 0

You use more significant figures. 5 sigfigs (1.0985) is more accurate than 2 sigfigs (1.0)

Naddik [55]2 years ago

4 0

Answer:

1)By using a measuring ruler

2)By measuring from 0cm

Explanation:

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How do you get 5 minutes to seconds

sergiy2304 [10]

There are 60 seconds in a minute.

This means that 5 minutes would be 60 times 5.
60×5 = 300

There are 300 seconds in 5 minutes.

5 0

3 years ago

Read 2 more answers

Two stones are launched from the top of a tall building. One stoneis thrown in a direction 30.0^\circ above the horizontal with

Butoxors [25]

Answer:

Part A)

t(1) > t(2), the stone thrown 30 above the horizontal spends more time in the air.

Part B)

x(f1) > x(f2), the first stone will land farther away from the building.

Explanation:

Part A)

Let's use the parabolic motion equation to solve it. Let's define the variables:

y(i) is the initial height, it is a constant.
y(f) is the final height, in our case is 0
v(i) is the initial velocity (v(i)=16 m/s)
θ1 is the first angle, 30°
θ2 is the first angle, -30°

For the first stone

$y_{f1}=y_{i1}+v*sin(\theta_{1})t_{1}-0.5gt_{1}^{2}$

$0=y_{i1}+16*sin(30)t_{1}-0.5*9.81*t_{1}^{2}$

$0=y_{i1}+8t_{1}-4.905*t_{1}^{2}$ (1)

For the second stone

$0=y_{i2}+16*sin(-30)t_{2}-4.905t_{2}^{2}$

$0=y_{i2}-8t_{2}-4.905t_{2}^{2}$ (2)

If we solve the equation (1) we will have:

$t_{1}=\frac{-8\pm \sqrt{64+19.62*y_{i}}}{-9.81}$

We can do the same procedure for the equation (2)

$t_{1}=\frac{8\pm \sqrt{64+19.62*y_{i}}}{-9.81}$

We can analyze each solution to see which one spends more time in the air.

It is easy to see that the value inside the square root of each equation is always greater than 8, assuming that the height of the building is > 0. Now, to get positive values of t(1) and t(2) we need to take the negative option of the square root.

Therefore, t(1) > t(2), it means that the stone thrown 30 above the horizontal spends more time in the air.

Part B)

We can use the equation of the horizontal position here.

First stone

$x_{f1}=x_{i1}+vcos(30)t_{1}$

$x_{f1}=0+13.86*t_{1}$

$x_{f1}=13.86*t_{1}$

Second stone

$x_{2}=x_{i2}+vcos(-30)t_{2}$

$x_{1}=0+13.86*t_{1}$

$x_{1}=13.86*t_{2}$

Knowing that t(1) > t(2) then x(f1) > x(f2)

Therefore, the first stone will land farther away from the building.

They land at different points at different times.

I hope it helps you!

3 0

3 years ago

When sunlight shines on a leaf the leaf looks green why does the leaf look green

KonstantinChe [14]

The correct answer is the third, It reflects the green light waves and absorbs most of the rest.

7 0

3 years ago

Read 2 more answers

A ball is spun around in circular motion such that it completes 50 rotations in 25 s.

Leokris [45]

Answer:

(A) The period of its rotation is 0.5 s (2) The frequency of its rotation is 2 Hz.

Explanation:

Given that,

a ball is spun around in circular motion such that it completes 50 rotations in 25 s.

(1). Let T be the period of its rotation. It can be calculated as follows :

$T=\dfrac{25}{50}\\\\T=0.5\ s$

(2). Let f be the frequency of its rotation. It can be defined as the number of rotations per unit time. So,

$f=\dfrac{50}{25}\\\\f=2\ Hz$

Hence, this is the required solution.

3 0

3 years ago

In the z-scheme ____ is the initial electron donor and ____ is the final electron acceptor.

Alenkinab [10]

In the z-scheme, water is the initial electron donor and NADP+ is the final electron acceptor.

Explanation: 

It is a process of photosynthesis. It occurs in photosynthetic chemical reaction. The z scheme is basically a term for representing the oxidation and reduction reaction occurring in plants during photosynthesis.

The water present in the chlorophyll pigment donates electrons and become the initial electron donor. Those electrons get transferred to NADP+ and forms NADPH. Thus, water acts as electron donor initially and so the final electron is NADP+.

6 0

3 years ago

Explain how you can improve the accuracy of a measurement. ​

Explain how you can improve the accuracy of a measurement.