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mojhsa [17]
3 years ago
9

A stationary speed gun emits a microwave beam at 2.10x10^10 Hz. It reflects off a car and returns 638 Hz lower. What is the spee

d of the car? (Unit=m/s)
Physics
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

The answer is 4.55 m/s!

Explanation:

I wish you luck with Acellus! We got 15 days left!

Please mark brainliest.

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Match the layers of the atmosphere with the description that best matches it according to the graph titled Temperature Profile.
Finger [1]
The correct matches are as follows:

<span>Troposphere
A) Layer closest to the Earth where all weather occurs

Mesosphere
</span>C) temperature remains constant as elevation increases<span>

Mesopause
</span>D) temperature remains at a constant zero degrees Celsius as elevation increases<span>


Stratosphere
</span>E) begins between 50-60km and decreases in temperature as elevation increases <span>


Stratopause
</span> B) temperature increases as elevation increases


Hope this answers the question. Have a nice day.
3 0
3 years ago
Read 2 more answers
An electron is confined to a one dimensional infinite potential well 150 pm. How much energy must it absorb if it is to jump to
igor_vitrenko [27]

Answer:

\Delta E=1.22\times 10^{-22}J

Explanation:

The energy of electron in any state is given by E=\frac{n^2h^2}{8mL^2} here h is planck's constant n is state of electron L is the infinte potential well m is the mass of electron

We know that h=6.67\times 10^{-34}

Potential well dimension = 150pm=150\times 10^{-12}m

Mass of electron =9.1\times 10^{-31}kg

So energy required to electron to jump from ground state to 3rd state

\Delta E=\frac{h^2}{8mL^2}\left ( 3^2-1^2 \right )

\Delta E=\frac{\left ( 6.67\times 10^{-34} \right )^2}{8\times 9.1\times 10^{-31}(150\times 10^{-12})^2}\left ( 9-1 \right )

\Delta E=1.22\times 10^{-22}J

7 0
3 years ago
Jason is taking a physical exam and has to do push ups for sixty seconds. He does 30 pushups in the sixty seconds. Each push up
Alexandra [31]

Answer: 2 seconds is the unit rate.

Explanation:

We know that Jason does 30 pushups in 60 seconds at a constant rate, and we know that each push up takes 2 seconds.

then, we can write this as 30 pushups/60 seconds = (1/2) pushups per second.

Here, two seconds represents the time needed to do one pushup, is the unit rate (this means that we need 2 seconds to have a unit "one pushup")

8 0
3 years ago
The magnitude of a negative of a vector is negative. O True O False
Paha777 [63]

Answer:

The given statement is false.

Explanation:

For any negative vector

\overrightarrow{r}=-x\widehat{i}-y\widehat{j}

The magnitude of the vector is given by

|r|=\sqrt{(-x)^{2}+(-y)^{2}}\\\\|r|=\sqrt{x^2+y^2}

As we know that square root of any quantity cannot be negative thus we conclude that the right hand term in the above expression cannot be negative hence we conclude that magnitude of any vector cannot be negative.

8 0
3 years ago
25 POINTS
nordsb [41]
An image that can be projected on a screen is a real image. A real image can be larger than the original object.
good luck

5 0
3 years ago
Read 2 more answers
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