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2 years ago

A tube filled with 50 quarts of water empties at a rate of 2.5 quarts per min

Mathematics

2 answers:

CaHeK987 [17]2 years ago

8 0

it will be emte in 20 hours

Debora [2.8K]2 years ago

6 0

Remark

If it does not have more water flowing in to take the place of the water flowing out, then the question can be solved by the formula below.

Formula

Total amount of water = the rate flowing out * the time to empty the container.

Givens

Amount of water = 50 quarts

Rate = 2.5 quarts / min

Solve

50 = 2.5 * t

t = 50 / 2.5

t = 20 quarts per minute. But there is a lot of possible variation to this question.

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Find the value of x A. 12 B. 4 C. 9 D. 14

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The answer to question
Find the value of x
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B.4

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2 years ago

The domain of a function is the set of all negative numbers. Which quadrant could the function be located in? Select two that ap

Marina86 [1]

Answer:

Step-by-step explanation:

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2 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$

= $P(- 0.7< Z< 2.1)$

= $(Z< 2.1) - (Z< -0.7)$

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= 0.7401

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2 years ago

The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y

kaheart [24]

Answer:

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Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

$d(x)=-4x^3+x^2$