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Vanyuwa [196]
3 years ago
13

I think I picked the right one not sure but really need help

Mathematics
2 answers:
Contact [7]3 years ago
6 0
The opposite of -4 is 4. (:
marishachu [46]3 years ago
3 0
The answer is positive 4
You might be interested in
A hose is leaking water at a rate of 2 oz/h. How many cups of water will leak out after 2 weeks?
Over [174]

Answer:

84 cups of water will leak out after 2 weeks

Step-by-step explanation:

* Lets how many how to change oz to cup

- One cup contains 8 oz

- We can use the ratio to solve this problem

- A hose is leaking water at a rate of 2 oz/h

- We need to find how many cups of water will leak out after 2 weeks

∵ The rate of the water leak out is 2 oz/hr

∵ 1 cup contains 8 oz

∴ 1 oz = \frac{1}{8} cup

∴ 2 oz = 2 × \frac{1}{8} = \frac{2}{8} = \frac{1}{4} cup

∴ The rate of the water leak out = \frac{1}{4} cup/h

∵ 1 day = 24 hours

∵ 1 week = 7 days

∴ 1 week = 7 × 24 = 168 hours

∵ The number of hours in 1 week is 168

∴ The number of hours in 2 weeks = 168 × 2 = 336 hours

⇒    cups    :    hours

⇒      \frac{1}{4}         :   1

⇒     x         :    336

- By using cross multiplication

∴ x = 336 × \frac{1}{4}

∴ x = 84

- x represents the number of cups of water leak out

<em>84 cups of water will leak out after 2 weeks</em>

5 0
3 years ago
Use the multiplier method to decrease £27 by 8%. You must show your working.
Nitella [24]

Answer:

decrease by 2.16

Step-by-step explanation:

Convert the problem to an equation using the percentage formula: P% * X = Y.

P is 10%, X is 150, so the equation is 10% * 150 = Y.

Convert 10% to a decimal by removing the percent sign and dividing by 100: 10/100 = 0.10.

3 0
2 years ago
Read 2 more answers
HELP ME PLEASE<br> RIGHT ANSWERS ONLYYY PLEASE
forsale [732]

The correct answer is

F. x = 8

8 0
3 years ago
HURRY QUICK!! Apply the distributive property to create an equivalent expression. 1/2 ( 6e - 3f - 3/4 )
tensa zangetsu [6.8K]

Answer:

1 2/6      3 3/4

Step-by-step explanation:

7 0
3 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
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