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madam [21]
3 years ago
9

NEED ASAP!! PlsssSSS WILL GIVE BRAINIEST!!

Mathematics
2 answers:
PtichkaEL [24]3 years ago
4 0

Answer:

sss similarities

Step-by-step explanation:

!!!!!!!!!!÷

solong [7]3 years ago
3 0
Similarities hope this helps you out
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$20000 is invested in an account that earned 6% p.A. Compounding yearly for 3 years. The interest rate then went up to 8% p.A. F
GuDViN [60]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for the first 3 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$20000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases}

\bf A=20000\left(1+\frac{0.06}{1}\right)^{1\cdot 3}\implies A=20000(1.06)^3\implies \boxed{A=2382.032} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Compound Interest Earned Amount \underline{for the next 4 years}}

\bf A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2382.032\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}

\bf A=2382.032\left(1+\frac{0.08}{1}\right)^{1\cdot 4}\implies A=2382.032(1.08)^4\implies \boxed{A\approx 3240.73} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{amount for this period}}{2382.032+3240.73}\implies 5622.762

4 0
4 years ago
Perform the indicated operations. x+1/3y+x-2/4y-x=3/6y
Varvara68 [4.7K]
The answer: 
_____________________________________________
x = (⅔)y ;

 y = 3x/2.
_____________________________________________
Given:

x + (⅓)y + x - (2/4)<span>y - x = (3/6)y ;
______________________________________ 
</span>
Take  the:  x + x - x = 1x + 1x - 1x = 2x - 1x = 1x = x ; 

and rewrite:

x + (⅓)y - (2/4)y = (3/6)y ;
_______________________________
 Note that:  (2/4)y = (<span>½)y ; 

        and:   (3/6)y = (</span><span>½)y ;  so;
___________________________
Rewrite as:
____________________________
</span>x + (⅓)y - (½)y = (½)y ;

Add "(½)y" to EACH SIDE of the equation;
_________________________________
    x  +  (⅓)y  -  (½)y  + (½)y = (½)y + (½)y ;

to get:  x +  (⅓)y = y ; 

x = 1y - (⅓)y = (3/3) y - (1/3)y - [ (3-1)/3] y = (⅔)y ; 

So:  x = (<span>⅔)y ;

In terms of "y" ; 

Given:  </span>(⅔)y = x ; Multiply each side of the equation by "3" ; 

3*[(⅔)y] = 3*x ;
 
 to get:  2y = 3x ;

Now, divide EACH SIDE of the equation by "2" ; to isolate "y" on one side of the equation; and to solve for "y" (in terms of "x"):

     2y / 2 = 3x / 2 ;

to get:  

      y = 3x/2 ;
___________________________________

6 0
4 years ago
The Davis family is moving, and they estimate that they will need a truck with about 1,250 cubic feet. Which truck do would be b
viktelen [127]
I need more info on this question
5 0
3 years ago
HELP QUICKLY PLZ!!!
Volgvan
<h2>Greetings!</h2><h3>1) If 7g = 315, then to get 1g you simply divide both sides by 7:</h3>

7 ÷ 7 = 1

315 ÷ 7 = 45

So g = 45

<h3> 2) If you divide 87 by h you get 4, you can simply reverse this and divide 87 by 3:</h3>

87 ÷ 3 = 29, so h is 29.


<h2>Hope this helps!</h2>
3 0
3 years ago
I NEED HELP PLZZZ
igor_vitrenko [27]
Hello there, 

This is a trick question Josh did not have an error. If you have 4x-8x in the numerator that becomes a -4x/2.
So then -4x/2= -2x
Josh was not wrong.

I hope this helped!
6 0
3 years ago
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