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serg [7]
3 years ago
6

Equipment costing $70,000 with a salvage value of $14,000 and an estimated life of 8 years has been depreciated using the straig

ht-line method for 2 years. Assuming a revised estimated total life of 6 years and no change in the salvage value, the depreciation expense for Year 3 would be
a. $10,500.
b. $9,333.
c. $14,000.
d. $7,000.
Business
2 answers:
Vlada [557]3 years ago
7 0

Answer:The answer is b

Explanation:

Cost - Salvage value /useful life

Cost =$70,000

Salvage value = $14,000

Useful life = 8years

Cost - Salvage value /useful life

70,000-14,000/8

= 56,000/8

=7000

Therefore yearly depreciation = $7,000

Provision for depreciation

Ist year cost - depreciation (70,000 - 7,000) = 63,000

2nd year cost - depreciation (63,000 - 7,000) = 56,000

Net Book value for the 3rd year = 56,000

Assuming a revised total life

= Net Book value /revised total life

= 56,000/6

= $9,333

Therefore depreciation expenses = $9,333

Shalnov [3]3 years ago
4 0

Answer:

depreciation expense =  $10500

correct option is a. $10,500

Explanation:

given data

Equipment costing  = $70,000

salvage value = $14,000

estimated life =  8 years

revised estimated total life = 6 years

to find out

depreciation expense

solution

we know that Depreciation expense per year is here express as

Depreciation expense =  (cost - Salvage value) ÷ useful life      ...................1

put here value we get

Depreciation expense  = \frac{70000 - 14000}{8}

Depreciation expense  = $7000 per year

so

book value as on beginning of year 3 is = 70000 - (7000 × 2)

book value as on beginning of year 3 is $56000

so

depreciation expense will be

depreciation expense =  \frac{56000 - 14000}{4}

depreciation expense =  $10500

correct option is a. $10,500

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\left[\begin{array}{cccc}Product&Sales&Weight&Cost\\Drumstick&4000&0.44&7230.22\\Breast&5000&0.56&9037.8\\\\Total&9000&1&16268\\\end{array}\right]

using market value:

\left[\begin{array}{cccc}Product&Sales&Weight&Cost\\Drumstick&6600&0.3367&5478\\Breast&13000&0.6633&10790\\\\Total&19600&1&16268\\\end{array}\right]

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In order to compute for the effective annual rate, the working equation would be [( 1 + i/n)^n] – 1.   The i corresponds to the nominal rate while n is the number of compounding periods per year which in this case is 12. The answer would be 5.116%.  

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Explanation:

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