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podryga [215]
3 years ago
11

The units digit of a two-digit exceeds twice the tens digit by 3. The sum of the digits is 6. Find the number

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

51

Step-by-step explanation:

y is the ten digit

and x the ones digit

y+x=6 -> x=6-y subtracted each side by y

2y+3=x

2y+3=6-y they both equal x so the equal each other

add y to both side to get rid of the y

minus 3 form both side to get rid of the 3

3y=3

y=1

plug it in

2(1)+3=x

5=x

51

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The quadratic equation 2x^2 + bx + 18 = 0 has a double root. Find all possible values of b.
Doss [256]
When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here 
a=2,
b=b,
c=18
and 
D=b^2-4ac=b^2-4*2*18=0 
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12

So in order that the given equation has double roots,  the possible values of b are ± 12.
4 0
3 years ago
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aleksandrvk [35]
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Vincent is watching a movie that last one hour and 37 minutes.he has watched 52 minutes so far how many minutes are left in the
Neporo4naja [7]
<h3>given:</h3>

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watched= 52 mins

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Answer:

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