Step-by-step explanation:
∆PQR similar to ∆ JKL
JK/KL= PQ/QR
6/12=3/QR
QR=3×2= 6
therefore, tan(R) = PQ/QR = 3/6=1/2
and, tan(J) = KL/JK =12/6=2


tan(J)=4.tan(R)
option D
Answer:
Let's solve for f.
x=5+4(x−4)f(7)
Step 1: Flip the equation.
28fx−112f+5=x
Step 2: Add -5 to both sides.
28fx−112f+5+−5=x+−5
28fx−112f=x−5
Step 3: Factor out variable f.
f(28x−112)=x−5
Step 4: Divide both sides by 28x-112.
f(28x−112)28x−112=x−528x−112
f=x−528x−112
Answer:
f=x−528x−112
Answer:
Car a travels (300) miles in 6 hours
Car B travels (200) miles in 5 hours
Car A speed is (50) miles per hour
Car B speed is(40) miles per hour.
Car A traveled (faster than) Car B.
The graph for Car A is(steeper than) the graph for Car B
Step-by-step explanation:

where x is starting location and y is the ending location

the rest we see once we have solve for distance and speed of the 2 cars
Answer:
2 3/8
Step-by-step explanation:
If what you're saying it 3 1/8 - 3/4 then...
3 1/8 - 3/4
3 1/8 - 6/8
25/8 - 6/8
19/8
2 3/8