Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
Answer:
The answer would be A and D, I just took the quiz
Step-by-step explanation:
Set the equations equal to each other
Subtract x from both sides
Divide both sides by -4
x=-1/2
579/3 fist you divid 5 by 3 than you subtract them and get two than you bring down your seven and have 27 divided by 3 and that is 9. than you bring down your last number and than you come up with an answer of 193.
Answer: Factoring using GCF 2x^2+34x+140-- 2(x+7)(x+10)
x^2+4x-77 --> (x-7)(x+11)
Step-by-step explanation: I don't know if these are 100 percent correct, since I'm learning these as well at the moment but I just wanted to help you out.
