Help me please I am so sad

Harman [31]

I think you meant to say

$\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}$

(as opposed to x approaching 2)

Since both the numerator and denominator are continuous at t = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}$

Because these expressions are continuous at t = 2, we can compute the limits by evaluating the limands directly at 2:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}$

6 0

2 years ago

2 sin^2(x) + 3sin(x) + 1 - 0 in radians

alexira [117]

This was a quadratic formula
sin is the y value
here is me solving it

7 0

2 years ago

Antonius the chef wants to cook several batches of lasagna and spaghetti for his restaurant. He plans to use at least 4.54.5 kil

yaroslaw [1]

Answer: No he does not meet both of his expectation by cooking 10 batches of spaghetti and 4 batches of lasagna.

Step-by-step explanation:

Since here S represents the number of batches of spaghetti and L represents the total number of lasagna.

And, the chef planed to use at least 4.5 kilograms of pasta and more than 6.3 liters of sauce to cook spaghetti and lasagna.

Which is shown by the below inequality,

$0.3S+0.65L \geq 4.5$ ----------(1)

And, $0.25S+0.8L >6.3$ --------(2)

By putting S = 10 and L = 4 in the inequality (1),

$0.3\times 10+0.65\times 4 \geq 4.5$

⇒ $5.6\geq 4.5$ (true)

Thus, for the values S = 10 and L = 4 the inequality (1) is followed.

Again By putting S = 10 and L = 4 in the inequality (2),

$0.25\times 10+0.8\times 4 >6.3$

⇒ $5.7>6.3$ ( false)

But, for the values S = 10 and L = 4 the inequality (2) is not followed.

Therefore, Antonius does not meet both of his expectations by cooking 10 batches of spaghetti and 4 batches of lasagna.

4 0

2 years ago

Read 2 more answers

The Reagan school marching band has three percussion musicians. How many musicians altogether in band ? 1/3 wood winds 1/6 percu

Artyom0805 [142]

1/6 percussion
1/3 wood winds = 2/6 (which is twice as many as percussion)
1/2 brass = 3/6 (which is three times as many as percussion)

So percussion = 3
wood winds = 6
brass = 9
all together = 3 + 6 + 9 = 18

6 0

3 years ago

Read 2 more answers

Type the correct answer in each box. If necessary, round your answers to the nearest hundredth.

disa [49]

Answer:

Perimeter = 32.44 units

Area = 30 square units

Step-by-step explanation:

Given

Vertices

A(2,8), B(16,2) and C(6,2)

WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

$d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\$

So the perimeter is:

$Perimeter=AB+BC+AC\\=15.23+10+7.21\\=32.44\ units$

Using hero's formula,

$s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units$

Rounding off will give us 30 square units ..

4 0

3 years ago