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Gennadij [26K]
3 years ago
12

Need answer asap.thanks​

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

0.46=\frac{23}{50}

Step-by-step explanation:

To write any decimal as a fraction you divide by 1 and multiply by a number (ranging from 10, 100, 1000 etc.) that will make 0.46 a whole number, this will explain:

Let x = \frac{0.46}{1}

10x = 10*\frac{0.46}{1} =\frac{4.6}{10}

100x = 100*\frac{0.46}{1}=\frac{46}{100} this is our perfect fraction, now we simplify later

100x - 10x = \frac{46}{100} -\frac{4.6}{10}

90x = \frac{46}{100} -\frac{4.6}{10} =0  this is to confirm both fractions are equal

x is the same as \frac{0.46}{1} as \frac{4.6}{10} as \frac{46}{100} but here x = \frac{46}{100} because a fraction has to have no decimals.

So  0.46 is equal any of these values, as a fraction, on the other hand, it's improperly equal to \frac{46}{100} = \frac{23}{50} here I divided by 2 to bring down the proper fraction. (fraction at its simplest form)

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12x - 29 find x please help
serg [7]

x =  \frac{29}{12}
or you can wirte like x ≈ 2.416
3 0
3 years ago
For the following exercises, determine whether each of the following relations is a function.
RSB [31]

Answer:

The relation {(2,1),(3,2),(-1,1),(0,-2)} is a function because the domain {2,3,-1,0} and range {1,2,1,-2} of the relation is paired exactly only once.

Step-by-step explanation:

The given relation is {(2,1),(3,2),(-1,1),(0,-2)}.

It is required to determine the relation is a function.

Step 1 of 1

The given relation is {(2,1),(3,2),(-1,1),(0,-2)}.

This relation shows that the domain of the relation {2,3,-1,0} is paired with one element of the range {1,2,1,-2}.

Hence, the relation is a function.

7 0
2 years ago
Shawntee has 21 coins all of them nickel and dimes that are worth $1.70. Write a system of equations and splve
Kipish [7]
N+d=21
5n+10d=170

so

multiply first equation by -5 and add to other one

-5n-5d=-105
<u>5n+10d=170 +</u>
0n+5d=65

5d=65
divide both sides by 5
d=13

sub back


n+d=21
n+13=21
minus 13 both sides
n=8




8nickles
13 dimes
8 0
3 years ago
Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4. Hint consider the
Verdich [7]

Answer:

<em>1364</em> is the number of possibilities for positive integers less than 1,00,000.

Step-by-step explanation:

<em>1. 5 digit numbers:</em>

We have 5 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 5 digit numbers:

4 \times 4 \times 4 \times 4 \times 4\\ \Rightarrow 1024

<em>2. 4 digit numbers:</em>

We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

4 \times 4 \times 4 \times 4 \\ \Rightarrow 256

<em>3. 3 digit numbers:</em>

We have 3 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 3 digit numbers:

4 \times 4 \times 4 \\ \Rightarrow 64

<em>4. 2 digit numbers:</em>

We have <em>2</em> places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 2 digit numbers:

4 \times 4 \\ \Rightarrow 16

<em>5. 1 digit numbers:</em>

We have 1 place here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 1 digit numbers:

4

We can add all the above possibilities to find the total.

So,  number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4 = 1024 + 256 + 64 + 16 + 4 = <em>1364</em>

3 0
3 years ago
Federal Rent-a-Car is putting together a new fleet. It is considering package offers from three car manufacturers. Fred Motors i
Viefleur [7K]

Answer:

  • 40 packages from Fred Motors
  • 20 packages from Admiral Motors
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Step-by-step explanation:

I would formulate the problem like this. Let f, a, c represent the numbers of packages bought from Fred Motors, Admiral Motors, and Chrysalis, respectively. Then the function to minimize (in thousands) is …

  objective = 500f +400a +300c

The constraints on the numbers of cars purchased are …

  5f +5a +10c >= 700

  5f +10a +5c >= 600

  10f +5a +5c >= 700

Along with the usual f >=0, a>=0, c>=0. Of course, we want all these variables to be integers.

Any number of solvers are available in the Internet for systems like this. Shown in the attachments are the input and output of one of them.

The optimal purchase appears to be …

  • 40 packages from Fred Motors
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  • 40 packages from Chrysalis

The total cost of these is $40 million.

8 0
4 years ago
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