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Gennadij [26K]
3 years ago
12

Need answer asap.thanks​

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

0.46=\frac{23}{50}

Step-by-step explanation:

To write any decimal as a fraction you divide by 1 and multiply by a number (ranging from 10, 100, 1000 etc.) that will make 0.46 a whole number, this will explain:

Let x = \frac{0.46}{1}

10x = 10*\frac{0.46}{1} =\frac{4.6}{10}

100x = 100*\frac{0.46}{1}=\frac{46}{100} this is our perfect fraction, now we simplify later

100x - 10x = \frac{46}{100} -\frac{4.6}{10}

90x = \frac{46}{100} -\frac{4.6}{10} =0  this is to confirm both fractions are equal

x is the same as \frac{0.46}{1} as \frac{4.6}{10} as \frac{46}{100} but here x = \frac{46}{100} because a fraction has to have no decimals.

So  0.46 is equal any of these values, as a fraction, on the other hand, it's improperly equal to \frac{46}{100} = \frac{23}{50} here I divided by 2 to bring down the proper fraction. (fraction at its simplest form)

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In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
3 years ago
Is 8/10 equal to 25/30
kotykmax [81]
No! 8/10 is not equal to 25/30 10 times 3 equals 30 but 8 times 3 equals 24 not 25. Th actual reaction would be 24/30
7 0
3 years ago
Read 2 more answers
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motikmotik
<span>A) 2x -5y +z = 1
B) 3 y + 2z = 5
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</span>
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3 years ago
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Iteru [2.4K]

Answer:

-30

Step-by-step explanation:

-x/10 = 3

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Answer:

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Step-by-step explanation:

P(event) = number of times event occurs/ total number of trials

Hi, You are the person I answered last time!

P(event) = 8/16

8/16 simplified is equaled to 1/2.

1/2 is equaled to 0.5

Again, I'm pretty sure this is right because it says experimental probability... I hope this helps!

8 0
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