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Tanzania [10]
3 years ago
10

What is the average of the first 50 positive odd integers

Mathematics
1 answer:
mote1985 [20]3 years ago
7 0
I think that the answer is 25
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Keith receives $25000 salary for working as a account. If keith spends 40% of his salary on expenses each year, then how much mo
Scrat [10]

Answer:

$25000 * 40% = 100.000

Step-by-step explanation:

4 0
3 years ago
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When dividing 878 by 31, a student finds a quotient of 28 with a remainder of 11. Check the students work, and use the check to
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878/3 is 28 with a remainder of 10! The error is when they subtracted 258-248 wrong
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Joe wants to place plants around each of four sides of a square yard. If he’s planned for each of the four sides to show six pla
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Answer:

21

Step-by-step explanation:

1 side = 6 plants (including one in the corner)

3 sides = 5 plants each

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7 0
3 years ago
coin $a$ is flipped three times and coin $b$ is flipped four times. what is the probability that the number of heads obtained fr
ivolga24 [154]

The probability that the number of heads obtained from flipping the two fair coins is the same is 35/128.

Probability:

Probability means the fraction of favorable outcome and the total number of outcomes.

So it can be written as,

Probability = Favorable outcomes / Total outcomes

Given,

The coin a is flipped three times and coin b is flipped four times.

Here we need to find the probability that the number of heads obtained from flipping the two fair coins is the same.

We know that,

There are 4 ways that the same number of heads will be obtained;

0, 1, 2, or 3 heads.

The probability of both getting 0 heads is

$\left(\frac12\right)^3{3\choose0}\left(\frac12\right)^4{4\choose0}=\frac1{128}$

Probability of getting 1 head,

$\left(\frac12\right)^3{3\choose1}\left(\frac12\right)^4{4\choose1}=\frac{12}{128}$

Probability of getting 2 heads is,

$\left(\frac12\right)^3{3\choose2}\left(\frac12\right)^4{4\choose2}=\frac{18}{128}$

And the probability of getting 3 heads is,

$\left(\frac12\right)^3{3\choose3}\left(\frac12\right)^4{4\choose3}=\frac{4}{128}$

Therefore, the probability that the number of heads obtained from flipping the two fair coins is the same is,

=> (1/128) + (12/128) + (18/128) + (4/128)

=> 35/128.

To know more about probability here

brainly.com/question/14210034

#SPJ4

4 0
1 year ago
What is 4and1/2 subtract 1/4
umka21 [38]

4 1/2=4 2/4

4 2/4-1/4=4 1/4 or 4.25

8 0
3 years ago
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