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barxatty [35]
3 years ago
12

Which of the functions have a range of all real numbers? Check all that apply.

Mathematics
2 answers:
____ [38]3 years ago
8 0
<h2>Hello!</h2>

The answer is:  The correct options are B. Tan(x) and C. Cot(x)

<h2>Why?</h2>

The range is the output of a function when we evaluate the function with inputs (domain), not all functions have a range of all real numbers, however it's more common to find functions without range or domain restrictions.

Both options B. Tan(x) and C. Cot(x) have a range of all real numbers while the functions Sec(x) and Csc (x) have a restricted range.

Sec(x) and Csc(x):

Domain, all real numbers.

Range, from -1 to 1 or  [-1,1]

Tan(x) and Cot(x):

Domain, all real numbers except \frac{\pi }{2}+-n\pi

Range, all real numbers.

Hence, the correct options are B. Tan(x) and C. Cot(x)

Have a nice day!

Svetach [21]3 years ago
6 0

Answer:

B. y = tan x  and  C. y = cot x

Step-by-step explanation:

Range:

range is defined as the set of values that any given function y=f(x), can take for which the x values are defined. It is the value that y can take for the values of x.

Given:

From the given options

the range of tanx and cotx are all real numbers

as the period of tanx and cotx are π

where as range of secx is all real numbers except π/2 + n*π i.e.

(-∞ , -1] U [1 , + ∞)

And range of cscx is all real numbers except n*π i.e.

(-∞ , -1] U [1 , + ∞)

So from the given option:

option B and C are correct while A and D are not !

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How to make this a simultaneous equation?
andriy [413]
Hello,

I suppose equations are:

x+y=3 (1)
x+2y=9 (2)

(2)-(1)==>y=6
(1)==>x=3-6

x=-3, y=6
Sol={(-3,6)}



7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
Which of the following triangles are right triangles? select all apply
Alex Ar [27]

Answer:

The following Triangles are Right Triangles:

1.  Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

Step-by-step explanation:

For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.

i.e.

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

AC² = 365² = 133225

AB² + BC² = 76² + 357² = 1333225

∴  AC² = AB² + BC²

Hence Δ ABC a Right Triangle.

For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

MT² = 845² = 71405

MI² + IT² = 123² + 836² = 714025

∴ MT² = MI² + IT²

Hence Δ MIT a Right Triangle.

For  Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

ML² = 101² = 10201

ME² + EL² = 20² + 99² = 10201

∴ ML² = ME² + EL²

Hence Δ MEL a Right Triangle.

7 0
3 years ago
Which function is described by values in the table?
Sveta_85 [38]

One way to approach this problem is to go ahead and find the actual equation in slope-intercept form.


The slope of the line thru (3,6) and (5,4) is m = (6-4) / (3-5), or -2/2, or -1.

Subbing the known values of m, x and y, we get:

4 = -(5) + b. Then b = 9.

The correct equation (representing the data values in the table) is y = -x + 9.


7 0
3 years ago
What is the range of g(x)?
Mila [183]

Answer:

2

Step-by-step explanation:

I just need for the points

5 0
2 years ago
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