A²-b²=(a-b)(a+b)
4x² - 25= (2x)²- 5² =(2x-5)(2x+5)
You do not have this choice, so the answer is D.None of the above.
Answer:
39.56%
Step-by-step explanation:
1. 1034-625=409
2. 409/1034= 0.39555126
3. 0.39555126x100= 39.555126
4. Round: 39.56%
U subtract 4x by 5x and then you add 3 by -21 and the answer is x=18
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
Step-by-step explanation:
If you divide 33 by 11 it’ll be 3 so we can cross B off, and A too because it’s not a double digit
So that leaves us with C & D.
If we divided 222 and 11 it would leave us with 10 which doesn’t match 11, so that leaves us with D
(Sorry if I didn’t’t explain right )
