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Nata [24]
3 years ago
7

a projectile is fired straight upward at 100m/s. how fast is it moving at the instant it reaches the top of its trajectory

Physics
1 answer:
Rus_ich [418]3 years ago
3 0
0m/s, when a projectile is at the top of a vertical ascent it has a velocity of 0 for an infinitesimally small amount of time before it begins to descend under the force of gravity.
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The nucleus in an iron atom has a radius of about 4.0 10-15 m and contains 26 protons. (a) What is the magnitude of the repulsiv
zhenek [66]

Answer:

The  repulsive electrostatic force between two of the protons is 14.4 N.

Explanation:

Given;

distance between the two protons, r = 4 x 10⁻¹⁵ m

charge of a proton, q = + 1.6 x 10⁻¹⁹ C

The repulsive electrostatic force between two of the protons is calculated by applying Coulomb's law;

F = \frac{k q_1 q_2 }{r^2} \\\\where;\\k \ is \ Coulomb's \ constant = 9\times 10^9 \ Nm^2/C^2 \\\\F = \frac{9\times 10^9 \  (1.6\times 10^{-19})^2}{(4 \times 10^{-15})^2} \\\\F = 14.4 \ N

Therefore, the  repulsive electrostatic force between two of the protons is 14.4 N.

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3 years ago
To calculate the heat needed to melt a block of ice at its melting point what do you need to know?
AnnyKZ [126]

Answer:

Explanation:

You are not raising the temperature of the block of ice. You are making it turn phase.

H = m * hf

That's the mass of the block and the latent heat of fusion.

D.

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3 years ago
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An electric motor is connected to a battery. The current flows through brushes to a commutator ring, which is attached to an ele
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URGENT PLEASE HELP!!!!! A spring has a spring constant of 105 N/m. If you compress the spring 0.1 m past its natural length, wha
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I believe it is 10.5?? 
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A 3874-kg rollercoaster is brought to the top of a 42m hill in 40 seconds,then drops 28m before the next hill.
Ede4ka [16]

(a) The work required to get the coaster to the top of the first hill is  1,594,538.4 J.

(b) The power required to bring the train to the top of the first hill is 39,863.46 W.

(c) The energy lost when the coaster drops is 531,512.8 J.

(d) The left at the bottom is determined as 1,063,025.6 J.

<h3>Work done to bring the rollercoaster top of the hill</h3>

W = Fn x d = mgh

W = 3874 x 9.8 x 42

W = 1,594,538.4 J

<h3>Power dissipated in bringing the rollercoaster on top hill</h3>

P = Fv

P = Fd/t

P = W/t

P = 1,594,538.4 /40 = 39,863.46 W

<h3>Energy lost when the coaster drops</h3>

E = 1,594,538.4 - (3874 x 9.8 x 28)

E = 531,512.8 J

<h3>Energy left at the bottom</h3>

E = 3874 x 9.8 x 28 = 1,063,025.6 J

Learn more about energy here: brainly.com/question/13881533

#SPJ1

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