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2 years ago

An object has a mass of 16 g and a density of 12 g/cm what is the volume of the object

Physics

1 answer:

julia-pushkina [17]2 years ago

8 0

The volume of an object that has a mass of 16 g and a density of 12 g/cm³ is 1.33cm³.

<h3>How to calculate density?</h3>

Density is a measure of a substance mass in relation with it's volume, which means that it can be calculated by dividing the mass of the substance by volume as follows:

Density = mass ÷ volume

According to this question, an object has a mass of 16 g and a density of 12 g/cm³. The volume can be calculated as follows:

Volume = 16g ÷ 12g/cm³

Volume = 1.33cm³

Therefore, the volume of an object that has a mass of 16 g and a density of 12 g/cm³ is 1.33cm³.

Learn more about volume at: brainly.com/question/952755

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A 2578-kg van runs into the back of a 825-kg compact car at rest. They move off together at 8.5 m/s. Assuming the friction with

allochka39001 [22]

Answer:

The initial speed of the car = 11.22 m/s

Explanation:

Law of conservation of energy: It states that when two bodied collide in a closed system, the sum of momentum before collision is equal to the sum of momentum after collision.

Note: A close system is one that is free from from external forces. E.g Frictional force.

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

m₁u₁ + m₂u₂ = (m₁ + m₂)V..................... Equation 1

Where m₁ = mass of the van, m₂ = mass of the car, u₁ = initial velocity of the van, u₂ = initial velocity of the car, V = Common velocity.

Given: m₁ = 2578 kg, m₂ = 825 kg, u₂ = 0 ( the car was at rest), V= 8.5 m/s

Substituting these values into equation 1, and solving for u₁

2578(u₁) + (825 × 0) = (2578 + 825)8.5

2578u₁ = 28925.5

Dividing both side of the equation by the coefficient of u₁

2578u₁/2578 = 28925.5/2578

u₁ = 11.22 m/s

The initial speed of the car = 11.22 m/s

3 0

3 years ago

Hermal energy is a form of... A. Potential energy. B. Kinetic energy. C. Chemical energy.

aev [14]

Thermal energy also known as 'heat energy' is a form of kinetic energy.

6 0

3 years ago

Please help !!! HELP

kozerog [31]

Answer:

The answer is C

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5 0

3 years ago

A neutron in a nuclear reactor makes an elastic head-on collision with the nucleus of a plutonium atom initially at rest. (a) Wh

olga55 [171]

Answer:

Fraction = 59049/60025

Explanation:

Let m be the mass of the neutron and M be the mass of the plutonium nucleus (at rest)

Now, formula for kinetic energy before collision is;

K_i = ½mu²

Formula for kinetic energy after collision is;

K_f = ½mv²

Where;

u is the velocity of the neutron before collision

v is the velocity of the neutron after collision.

From collision principle where momentum before collision equals momentum after collision, we can say that;

(m - M)u = (m + M)v

Thus,

v = [(m - M)u]/(m + M)

Putting [(m - M)u]/(m + M) for v in the final kinetic energy equation gives;

K_f = ½m([(m - M)u]/(m + M))²

K_f = ½mu²((m - M)²/(m + M)²)

To get the fraction of the neutron's kinetic energy is transferred to the plutonium nucleus, it is simply;

K_f/K_i = [½mu²((m - M)²/(m + M)²)]/½mu²

This gives;

K_f/K_i = ((m - M)²/(m + M)²)

But mass of plutonium = 244m

Thus;

K_f/K_i = ((m - 244m)²/(m + 244m)²)

K_f/K_i = 59049m²/60025m²

K_f/K_i = 59049/60025

4 0

3 years ago

How do you add scientific notation if the problem is like this: 3.72 x 10^9 + 5.46 x 10^8?

Crazy boy [7]

You can only add or subtract numbers in scientific notation if they have
the same power of 10. If they're different, then you have to change one
to match the other one.

Here are both ways to do your example:

3.72x 10^9 = 37.2x10^8

(37.2 x 10^8)+(5.46 x 10^8) = (37.2+5.46) x 10^8 = 42.66x10^8 = 4.266x10^9

=======================

5.46 x 10^8 = 0.546 x 10^9

3.72 x 10^9 + 0.546 x 10^9 = (3.72 + 0.546) x 10^9 = 4.266 x 10^9

3 0

4 years ago