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julia-pushkina [17]
3 years ago
9

To solve a problem, we often _________ the given information into algebraic expressions and equations.

Mathematics
1 answer:
bulgar [2K]3 years ago
4 0
\frac{-b\pm\sqrt{b^2-4ac}}{4a}
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Dawson rakes leaves in his neighborhood. The equation y = 10x represents the amount of money he earns. What is the constant of p
Dafna11 [192]

Answer:

idk for sure but id say 10x

Step-by-step explanation:

5 0
3 years ago
The frequency table shows how many visits to the library students in a school have made in the last month.
vfiekz [6]
<h3>Answer:  2.8</h3>

=======================================================

Explanation:

Multiply each visit count with their corresponding frequency.

Examples:

  • 0*12 = 0 for the first row.
  • 1*366 = 366 for the second row
  • 2*53 = 106 for the third row

and so on...

I recommend making a third column like this

\begin{array}{|c|c|c|} \cline{1-3}\text{Visits} & \text{Frequency} & \text{Visits*Frequency}\\\cline{1-3}0 & 12 & 0\\\cline{1-3}1 & 366 & 366\\\cline{1-3}2 & 53 & 106\\\cline{1-3}3 & 52 & 156\\\cline{1-3}4 & 155 & 620\\\cline{1-3}5 & 243 & 1215\\\cline{1-3}\end{array}

That way you can keep track of all the results in an organized way.

Then add everything in the third column

0+366+106+156+620+1215 = 2463

Divide this sum over the total frequency (12+366+53+52+155+243 = 881) and we'll get the mean

2463/881 = 2.7956867

Rounding to one decimal place gets us to 2.8 as the final answer.

-------------

The much longer way to do this is to imagine 12 copies of "0", 366 copies of "1", 53 copies of "2", and so on. We'll have an extremely large data set of 881 items inside it. As you can see, this second method is definitely not recommended to actually carry out. Rather it's helpful to have this as a thought experiment to see why we revert to multiplication instead.

Eg: Imagine adding 155 copies of "4". A shortcut is to simply say 4*155 = 620

4 0
2 years ago
Read 2 more answers
What is a common denominator for 1/6 and 3/5
d1i1m1o1n [39]

Answer:

30

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the following product ^3sqrt16x^7*^3sqrt12x^9
hichkok12 [17]

Answer:

4x^5\sqrt[3]{3x}

Step-by-step explanation:

Given

\sqrt[3]{16x^7}\left(\sqrt[3]{12x^9}\right)\\\sqrt[3]{4^{2} x^7}\sqrt[3]{4(3)x^9}\\  4^\frac{2}{3} . x^\frac{7}{3} . 4^\frac{1}{3} . 3^\frac{1}{3} . x^\frac{9}{3}\\  4^\frac{2+1}{3} .  3^\frac{1}{3}. x^\frac{9+7}{3} \\4^\frac{3}{3} . 3^\frac{1}{3}. x^\frac{16}{3}\\ 4\sqrt[3]{3x^16}

4\sqrt[3]{3} . x^\frac{16}{3} \\4\sqrt[3]{3} . x^\frac{15}{3} .x^\frac{1}{3} \\4\sqrt[3]{3} . x^5 .x^\frac{1}{3} \\4x^5\sqrt[3]{3x} !

7 0
3 years ago
Read 2 more answers
during the week of the country fair, fifteen thousand, six hundred nine entry tickets were sold. Is it correct to write the numb
dezoksy [38]

Answer:

No. It's 15,609

Step-by-step explanation:

The fifteen thousand represents the 15,000

The six hundred is 600

The nine is 9.

So it is 15,609

4 0
3 years ago
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