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Arlecino [84]
3 years ago
9

Clare buys 5 tickets for the high

Mathematics
2 answers:
mr_godi [17]3 years ago
4 0

Answer:

$45

Step-by-step explanation:

5 x 9

suter [353]3 years ago
3 0

Answer: $45

Step-by-step explanation: if she buys 5 tickets and each of them are $9 then you multiple the two numbers to get $45

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Solve for x.<br> A) 6<br> C) 4<br> B) 12<br> D) 2
arsen [322]

Answer:

x=4

Step-by-step explanation:

go it right on edge

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3 years ago
The quadratic equation 8x²+12x-14 has two real roots. What is the sum of the squares of these roots?
mars1129 [50]

Answer:

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

The sum of the squares of these roots is \frac{-3}{2}

Step-by-step explanation:

The given quadratic equation is 8x^2+12x-14 has two real roots.

To find the roots .

8x^2+12x-14=0

Dividing the above equation by 2

\frac{1}{2}(8x^2+12x-14)=\frac{0}{2}

4x^2+6x-7=0

For quadratic equation ax^2+bx+c=0 the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where a and b are coefficents of x^2 and x respectively, c is a constant.

For given quadratic equation

a=4, b=6, c=-7

x=\frac{-6\pm\sqrt{6^2-4(4)(-7)}}{2(4)}

=\frac{-6\pm\sqrt{36+112}}{8}

=\frac{-6\pm\sqrt{148}}{8}

=\frac{-6\pm\sqrt{37\times 4}}{8}

=\frac{-6\pm\sqrt{37}\times\sqrt{4}}{8}

=\frac{-6\pm\sqrt{37}\times 2}{8}

=2\frac{(-3\pm\sqrt{37})}{8}

=\frac{-3\pm\sqrt{37}}{4}

x=\frac{(-3\pm\sqrt{37})}{4}

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

Now to find the sum of the squares of these roots

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}

=\frac{-6}{4}

=\frac{-3}{2}

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}

Therefore the sum of the squares of these roots is \frac{-3}{2}

3 0
3 years ago
Stacey is making a trail mix for the school field trip. The recipe shows the amount of each ingredient needed to make 6 bags. If
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3 years ago
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Can someone help me with this ?
navik [9.2K]

Answer:

SSS --> SAS --> AAS --> SAS --> HL --> SSS --> ASA --> AAS --> HL --> SAS --> HL

Step-by-step explanation:

To do this problem, look at the angles that are marked congruent as well as the sides. Then look at the order that the angles and sides are placed. If it is SSS, then that means three sides are marked congruent. SAS means the order of the side and angles would be side then angles then another side. AAS means angle then angle then side. HL is when you have a right triangle and one of the legs are congruent as well as the hypotenuse. ASA means an angle then side then another angle.

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