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Valentin [98]
3 years ago
7

When computers connect to one another to share information, but are not dependent on each other to work, they are connected thro

ugh a _________ network.
Computers and Technology
1 answer:
kap26 [50]3 years ago
6 0
A peer-to-peer network, I believe.
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What are the benefits of using an ordered list vs. an unordered list? What are the costs?
Rashid [163]

Answer:

The main benefit of the ordered list is that you can apply Binary Search( O( n log n) ) to search the elements. Instead of an unordered list, you need to go through the entire list to do the search( O(n) ).

The main cost of the ordered list is that every time you insert into a sorted list, you need to do comparisons to find where to place the element( O( n log n) ). But, every time you insert into an unsorted, you don't need to find where to place the element in the list ( O(1) ). Another cost for an ordered list is where you need to delete an element, you have an extra cost rearranging the list to maintain the order.

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2 years ago
What do work places allow a company to do
anygoal [31]
D. They provide a platform for collaboration
8 0
3 years ago
What would be the most popular piece of technology on Earth?
spin [16.1K]

Answer:

the smart phone

Explanation:

It is the most widley used and accepted

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3 years ago
Read 2 more answers
To solve the difficulty of scaling memory organization, memories are physically organized into a ____-dimensional organization.
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Answer: two

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Organizational memory is simply referred to as the accumulation of data or information that have been created for a particular organization.

To solve the difficulty of scaling memory organization, memories are physically organized into a two dimensional organization.

3 0
3 years ago
Q1). Write a python program to pass a list to a function and double the odd values and half even values of a list and display li
zepelin [54]

Answer:

\textsf{\large{\underline{Solution}:}}

The given problem is solved using language - Python.

def f(x):

   new_list=[]

   for i in x:

       if i%2==0:

           new_list.append(i//2)

       else:

           new_list.append(i*2)

   return new_list

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(my_list)

print('Modified List:',my_list)

\textsf{\large{\underline{Logic}:}}

  1. Create a new list.
  2. Iterate over the list passed into the function.
  3. Check if the element is even or not. If true, append half the value of element in the list.
  4. If false, append twice the value of the element in the list.
  5. At last, return the new list.

There is another way of doing this - By using map() function.

—————————————————————————————

def f(x):

   return list(map(lambda x:x//2 if x%2==0 else 2*x,x))

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(2my_list)

print('Modified List:',my_list)

—————————————————————————————

\textsf{\large{\underline{O{u}tput}:}}

Original List: [1, 2, 3, 4, 5]

Modified List: [2, 1, 6, 2, 10]

8 0
2 years ago
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