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3 years ago

13

HELP SO I DON’T FAIL! WILL RECEIVE BRAINLIEST! Use a calculator to find the r-value of these data. Round the value to three deci

mal places.

2 answers:

Xelga [282]3 years ago

5 0

A is the answer

for apex

Flauer [41]3 years ago

3 0

The answers C. this is the true answer okkkkkkk

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An auto insurance company pays 12% commission to its agents for each new insurance policy they sell. How much commission does an

Darina [25.2K]

Answer:

120

Step-by-step explanation:

0.12 × 1000 = 120

___

The amount of commission is the product of the commission rate and the amount on which commission is paid.

5 0

3 years ago

CAN SOMEONE PLEASE PLEASE PLEASE HELP ME, YOU’LL GET FREE EASY POINTS IF YOU GIVE ME THE RIGHT ANSWER !!

bekas [8.4K]

Answer:

reflection across BC
the image of a vertex will coincide with its corresponding vertex
SSS: AB≅GB, AC≅GC, BC≅BC.

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

<h3>1.</h3>

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

__

<h3>2.</h3>

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

__

<h3>3.</h3>

The markings on the figure show the corresponding parts to be ...

side AB and side GB
side AC and side GC
angle ABC and angle GBC
angle BAC and angle BGC

And the reflexive property of congruence tells us BC corresponds to itself:

side BC and side BC

There are four available congruence theorems applicable to triangles that are not right triangles

SSS -- three pairs of corresponding sides
SAS -- two corresponding sides and the angle between
ASA -- two corresponding angles and the side between
AAS -- two corresponding angles and the side not between

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

Corresponding sides are listed above. Here, we list them again:

AB and GB; AC and GC; BC and BC

SAS

One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

3 0

1 year ago

Read 2 more answers

ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

Now we can solve for y:

$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0

3 years ago

What is the square root 6n carried to the power of 2/3 in radical form

BaLLatris [955]

Answer: $\sqrt[3]{6n}$

Step-by-step explanation:

We have the following expression:

$(\sqrt{6n})^{\frac{2}{3}}$

Which can be written as follows:

$((6n)^{\frac{1}{2}})^{\frac{2}{3}}$

Multiplying the exponents:

$(6n)^{\frac{1}{3}}$

Writing in radical form we finally have the result:

$\sqrt[3]{6n}$

7 0

3 years ago

The sum of four consecutive odd integers is -72. Write an equation to model this situation, and ind the values of the four integ

Nutka1998 [239]

Answer:

equation: (x-3) +(x-1) +(x+1) +(x+3) = -72
values: -21, -19, -17, -15

Step-by-step explanation:

When dealing with consecutive integers, it often simplifies the problem to work with their average value. We know the average value of the integers in this problem is the even integer between the middle two. We can call it x, and write the equation ...

(x-3) +(x-1) +(x+1) +(x+3) = -72

This simplifies to ...

4x = -72 . . . . . . . we knew this before we wrote the above equation, since the sum of 4 numbers is 4 times their average.

x = -18 . . . . . . . . the middle number of the sequence

So, the numbers are:

-18-3 = -21
-18-1 = -19
-18+1 = -17
-18+3 = -15

_____

A more conventional approach is to define the variable as the integer at one end or the other of the sequence. If we make it be the lowest number, then the equation is ...

(x) +(x +2) +(x +4) +(x +6) = -72

and that simplifies to ...

4x +12 = -72 . . . . . collect terms

4x = -84 . . . . . . . . subtract 12

x = -21 . . . . . . . . . . divide by 4

Now, the other three numbers are found by adding 2, 4, and 6 to this one.

3 0

3 years ago