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3 years ago

Write how you would use numbers to investigate each object

Physics

1 answer:

Nata [24]3 years ago

5 0

For the 1st imagine you can use numbers such as to count the eyes or the legs. The second image you could count how many circles are in the image. The third one you could use numbers to count the wheels.

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Two trains approach each other on parallel tracks. Each has a speed of 95 kph relative to the ground. If they are initially 8.5

aliya0001 [1]

Answer: 2.83 minutes

Explanation:

It is understood that trains are approaching. That is, they have speeds of equal magnitude but opposite. When train A travels x meters northbound, then train B travels the same distance southbound.

Therefore trains approach at a speed of:

$V = 95 +95 = 190\ km / h$

Then:

$V = \frac{x}{t}\\\\t = \frac{x}{V}$

Where x is the distance between the trains

$x = 8.5\ km$

So the time in which both trains meet is:

$t =\frac{8.5\ km}{180\ \frac{km}{h}}\\\\t=0.04722\ hours$

This is:

$0.04722*\frac{60\ minutes}{1\ hour} = 2.83\ minutes$

<em />

<em>How long will it be before they reach one another ?</em>

<h3>2.83 minutes</h3>

3 0

3 years ago

A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position

irga5000 [103]

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

<em>Mass of the ball, m = 2.4 kg</em>

<em />

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

$f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz$

The angular frequency of the oscillation is calculated as follows;

$\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s$

The force constant of the spring is calculated as follows;

$\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m$

Learn more about general wave equation here: brainly.com/question/25699025

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3 years ago

PLEASE PLEADE HELP!?!?

MA_775_DIABLO [31]

A. since the universe has no matter or energy on the outside

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3 years ago

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A caterpillar travels straight for 3 cm, and then turns left and crawls 4 centimeters farther. If its final position is east of

Romashka-Z-Leto [24]

3-squared + 4-squared = 5-squared

The bug's displacement is 5cm east.

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4 years ago

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An example of constant velocity

pashok25 [27]

Some examples of constant velocity (or at least almost- constant velocity) motion include (among many others): • A car traveling at constant speed without changing direction. A hockey puck sliding across ice. A space probe that is drifting through interstellar space.

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3 years ago