Answer:
Explanation:
Given that
R= 0.19 m
r= 0.28 m
I= 2.6 A
We know that
A= Area of loop
dE/dt= rate of change of electric filed
I=Displacement current
Here r>R
So A=π R²
Now by putting the values
Answer:
30%
Explanation:
Efficiency = useful work / heat absorbed x 100
= 120/400 x 100
= 0.3 x 100
= 30%
Answer:
1) 1.67eV
2) 505nm
Explanation:
The maximum kinetic energy of photoelectrons ,
KEmax=λhc−W=(0.3×10−6)(1.6×10−19)(6.62×10−34)(3×108)eV−2.46eV=1.67eV
If λ0 is the cut-off wavelength, W=λ0hc
or λ0=Whc=2.46×1.6×10−19(6.62×10−34)(3×108)=5.05×10−7m=505×10−9=505nm
<em>We know that the work function is the minimum photon energy for taking place of photoelectric effect. </em>
Answer:
20 m/s
Explanation:
Height (s)= 20m
acceleration (a) = 10 m/s^2
v=?
we know,
V^2= U^2 + 2as. (U is initial velocity)
or,. V^2 = 0 + 2 × 10 × 20
or, V^2 = 400
or,. V = 20 m/s
