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2 years ago

11

if the emission lines in the spectrum of one object are more strongly blueshifted than those from a second object, then the firs

t object is moving

1 answer:

Lelu [443]2 years ago

6 0

Answer:

Toward us faster than the second object

Explanation:

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A very humble bumble bee is flying horizontally due North at a constant speed of 3.11 m/s. At the current location of the bumble

Reil [10]

To solve this problem we will apply the concepts of the Magnetic Force. This expression will be expressed in both the vector and the scalar ways. Through this second we can directly use the presented values and replace them to obtain the value of the magnitude. Mathematically this can be described as,

$\vec{F_B} = q(\vec{V}\times \vec{B})$

$F_B = q|v||B| sin\theta$

Here,

q = Charge

v = Velocity

B = Magnetic field

$\theta = \text{Angle between } \vec{B} \text{ and } \vec{V}$

Our values are given as,

$\theta = 35.7\°$

$q = 22.5*10^{-9}C$

$B = 1.05*10^{-5}T$

$v = 3.11m/s$

Replacing,

$F_B = (22.5*10^{-9}C)(3.11 \times 1.05*10^{-5}) sin(35.1\°)$

$F_B = 4.224*10^{-13}N$

Therefore the size of the magnetic force acting on the bumble bee is $4.22*10^{-13}N$

3 0

3 years ago

What can we say about Gamma waves on<br> the electromagnetic spectrum?

sladkih [1.3K]

Answer: Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions. Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.

Explanation: :)

6 0

2 years ago

The needle in the following diagram rotates around a fixed point in the middle. Based on the information given, what way will th

Ronch [10]

Answer:

nods 40th anniversary rid off e 49en9 snns

3 0

3 years ago

What is the average acceleration of a rocket that travels 400m in 5s if it starts from rest?

Pavel [41]

Answer:

<h2>32m/s^2</h2>

Explanation:

We want to find the acceleration based on the given data

Given

distance s=400m

time t= 5s

u= 0m/s since it started from rest

We apply the following expression

s=ut+1/2at^2

substituting we have

400=0*5+1/2*a(5)^2

400=25a/2

cross multiply

25a=400*2

25a=800

divide both sides by 25 we have

a=800/25

a=32m/s^2

The acceleration is 32m/s^2

4 0

3 years ago

Photons with shorter wavelengths have larger

Zarrin [17]

i think photons with shorter wavelengths have larger speed.

I apologise if its incorrect.

7 0

3 years ago