Answer:
6 m/s²
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 30 m/s
Time (t) = 5 s
Acceleration (a) =..?
Acceleration is defined mathematically as:
Acceleration (a) = Velocity (v) /time (t)
a = v /t
With the above formula, we can obtain the acceleration of the object as follow:
Velocity (v) = 30 m/s
Time (t) = 5 s
Acceleration (a) =..?
a= v/t
a= 30/5
a = 6 m/s²
Therefore, the acceleration of the object is 6 m/s² due East.
Answer:
aaa
Explanation:
= Mass of the Earth = 5.98 × 10²⁴ kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
= Distance from the center of the Moon to the center of Earth = 6371000 m
= Distance from the center of the earth center to sun center
= Mass of moon = 
M = Mass of sun = 
Hence the force of moon on earth is 0.00566 times the force of earth on moon center to center
In this case, the PWC will head for the dock. This is because, power needs to be applied in order to maintain steering control. If the throttle is left to idle or if the engine is turn off during operation, all steering control will be lost. In each of this situation, the PWC will continue in the was headed before the engine was turned off or before the throttle was left to idle.
Explanation:
Comparison Chart
Basis For Comparison CFL Bulb LED Bulb
Definition The CFL is defined as the lamp which uses the low pressure mercury vapour gas for producing the visible light It is a PN junction diode which produces light when current passes through it in the forward direction.
Stand For Compact Fluorescent Lamp Light Emitting Diode
Working principle The electrons of mercury when excited emits ultraviolet light. This ultraviolet light when strikes with the fluorescent coating glass converts it into the visible light. The semiconductor material which emits light with the passage of current.
Power Consumption More Less
Mercury Contain Not contain
Destruction Difficult Easy
Efficient Less More
Ballast Requires Not requires
Lifespan 10,000 hours 50,000 hours and more.
Turn on Intensity Delay Quick
Expensive Less More
Answer:
The focal length of eye piece is 6.52 cm.
Explanation:
Given that,
Angular Magnification of the microscope M = -46
the distance between the lens in microscope L= 16 cm
The focal length of objective f₀ = 1.5 cm
Normal near point N = 25 cm
Have to find focal length of eye piece f ₙ =?
The angular magnification is given by
M ≈ - (L-fₙ)N/f₀fₙ
Rearranging for fₙ
fₙ =L(1 - Mf₀/N)⁺¹
=18/2.76
fₙ = 6.52 cm
The focal length of eye piece is 6.52 cm.
