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2 years ago

Please help!!!!!!!!!! hurrrrrryyyyyyy!!!!!!!!!!!

Mathematics

2 answers:

yawa3891 [41]2 years ago

6 0

Answer:

Step-by-step explanation:

The measure of the inscribed angle is half the measure of intercepted angle.

∠ABC $= \dfrac{1}{2} * 120\\$

= 60°

Maksim231197 [3]2 years ago

5 0

Answer:

∠ ABC = 60°

Step-by-step explanation:

the measure of an inscribed angle is hal the measure of its intercepted arc.

∠ ABC = $\frac{1}{2}$ AC = $\frac{1}{2}$ × 120° = 60°

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Calibrating a scale:

lana66690 [7]

Answer:

We conclude that the calibration point is set too high.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 1000 grams

Sample mean, $\bar{x}$ = 1001.1 grams

Sample size, n = 50

Alpha, α = 0.05

Population standard deviation, σ = 2.8 grams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 1000\text{ grams}\\H_A: \mu > 1000\text{ grams}$

We use One-tailed(right) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{ 1001.1 - 1000}{\frac{2.8}{\sqrt{50}} } = 2.778$

Now, $z_{critical} \text{ at 0.01 level of significance } = 2.326$

Since,

$z_{stat} > z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. We accept the alternate hypothesis. We conclude that the calibration point is set too high.

6 0

3 years ago

The following data shows the quarterly profit (in thousands of dollars) made by a particular company in the past 3 years.

laiz [17]

Answer:

208.82 ; 61.33

Step-by-step explanation:

Given the data:

Year Quarter Profit ($1000s)

1 1 45

1 2 51

1 3 72

1 4 50

2 1 49

2 2 45

2 3 79

2 4 54

3 1 42

3 2 58

3 3 70

3 4 56

The 3 period moving average :

Yr Qtr Profit ($1000s)Pt ____ Ft ____ e=(PT-Ft)²

1 _ 1 ___45 __

1 _ 2 __ 51 __

1 _ 3 __ 72 __

1 _ 4 __ 50 ______________56 ____ 36

2 _ 1 __ 49 ______________57.67__ 75.17

2 _ 2__ 45 ______________57 ____ 144

2 _ 3__ 79 ______________48 ____961

2 _ 4__ 54 ______________57.67 _ 13.47

3 _ 1__ 42 ______________59.33__300.33

3 _2 __ 58 ______________58.33__ 0.11

3 _ 3__ 70 ______________51.33__ 348.57

3 _ 4 __56 ______________56.67__0.45

MSE = Σ(Pt - Ft)² ÷ n

MSE = (36+75.17+144+961+13.47+300.33+0.11+348.57+0.75) ÷ 9

= 208.82

Forecast for next quarter :

(58 + 70 + 56) / 3 = 184 /3 = 61.33

8 0

3 years ago

Three fifths of one sixths evaulate expression

sukhopar [10]

3/5 of 1/6 is written as

3/5 x 1/6

Multiply both the numerator and denominators together:

3x1 / 5*6 = 3/30, reduces to 1/10.

The answer is 1/10.

3 0

3 years ago

Read 2 more answers

PLEASE HELP!!This is joshs solution for the equation x^2-6x-7=0: x^2-6x-7=0

iren [92.7K]

Answer:

no. see below

Step-by-step explanation:

This much of Josh's working is correct:

x^2-6x=7

x^2-6x+9=7+9

(x-3)^2=16

At this point Josh apparently overlooked the fact that he needed to take the square root of both sides of the equation. Had he done that, he would have ...

x -3 = ±4

x = 3+4 . . . or . . . 3 -4

x = 7 or -1

_____

Josh reported values of x that would match ...

x -3 = ±16

He <em>violated the equal sign</em> by taking the square root on the left, and multiplying by ±1 on the right. Doing different operations on the two sides of the equation will mean the value of x is changed to something other than what you're looking for.

4 0

3 years ago

Find the surface area of this net.

Elden [556K]

Answer:

Step-by-step explanation:

First, let's find the surface area of both the triangles

5x3=15

So, the surface area of the triangles is 15 sq.cm

Now, let's find the surface area of the base (large rectangle in the middle)

12x8=?

10x8=80

2x8=16

80+16=96

12x8=96

So, the surface area of the base, is 96sq.cm

Now, let's find the surface area of both of the side rectangles

12x5=60

60x2=120

So, the surface area of the two side rectangles is 120sq.cm

Now, let's find the total surface area by adding all of our answers.

120+96=216

216+15=231

<h2>So hence, the surface area of this net is 231cm²</h2>

3 0

2 years ago