Using a discrete probability distribution, it is found that:
a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
c) The expected value is of 1.3 lawns mowed on a randomly selected day.
<h3>What is the discrete probability distribution?</h3>
Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:
Item a:
P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.
Item b:

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.
Item c:
The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:
E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.
The expected value is of 1.3 lawns mowed on a randomly selected day.
More can be learned about discrete probability distributions at brainly.com/question/24855677
Ken grew .425 of an inch more than Sang
They are terms<span> that contain the same variables raised to the same power. Only the numerical coefficients are different. In an expression, only </span>like terms<span> can be combined. We combine </span>like terms<span> to shorten and simplify algebraic expressions, so we can work with them more easily.</span>
Answer:
A≈176.71
Step-by-step explanation:
Answer: b=4(10)^1/2
Step-by-step explanation:
Distance Formula: a^2+b^2=c^2
6^2+b^2=14^2
36+b^2=196
b^2=160
b^2=10*16
b=(10*16)^1/2
b=4(10)^1/2