Question

For the following equilibrium: 3A + B = 20 If equilibrium concentrations are [A] = 1.1 M and [B] = 1.4 M, and Kc = 11.3, what is the equilibrium concentration of C? • Your answer should have two significant figures. Provide your answer below:

Answer 1

Answer : The equilibrium concentration of C is 4.6 M

Solution :  Given,

Concentration of $A$ at equilibrium = 1.1 M

Concentration of $B$ at equilibrium = 1.4 M

$K_c=11.3$

First we have to calculate the value of equilibrium constant.

The given equilibrium reaction is,

$3A+B\rightleftharpoons 2C$

The expression of $K_c$ will be,

$K_c=\frac{[C]^2}{[A]^3[B]}$

$11.3=\frac{[C]^2}{(1.1)^3\times (1.4)}$

$[C]=4.6M$

Therefore, the equilibrium concentration of C is 4.6 M