Answer:
The answer is 5 mol
Explanation:
Number Of Moles = Mass Of Substance ÷ Mass Of One Mole
Mass of NaOH = Molar Mass of Sodium + Oxygen + Hydrogen
23 + 16 + 1
40 g/mol
Number of Mole = 200/40 = 5 mol
Thus, The number of Moles in 200 grams of Sodium hydroxide is 5 mol
<u>-TheUnknownScientist 72</u>
In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
Learn more: brainly.com/question/10079361
Answer:
2H on 3H
Explanation:
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Answer:
Because the neutrons equal the number of protons
Explanation:
So if u have 16 protons u have 16 neutrons