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timurjin [86]
3 years ago
15

Compound A is an organic compound which contains Carbon, Hydrogen and Oxygen. When 0.240g of the vapour of A is slowly passed ov

er a large quantity of heated Copper (II) oxide, CuO, the compound A is completely oxidized to carbon dioxide and water. Copper is the only other product of the reaction. The products are collected and it is found that 0.352g of CO2 and 0.144g of H2O are formed. Questions :
1) Calculate the mass of carbon present in 0.352g of CO2
2) Use this value to calculate the amount in moles of carbon atoms present in 0.240g of A
Chemistry
1 answer:
vesna_86 [32]3 years ago
4 0

(a)   In this section, give your answers to three decimal places.

(i)

Calculate the mass of carbon present in 0.352 g of CO

2

.

Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g

of

A

.

(ii)

Calculate the mass of hydrogen present in 0.144 g of H

2

O.

Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g

of

A

.

(iii)

Use your answers to calculate the mass of oxygen present in 0.240 g of

A

Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g

of

A


(b)

Use your answers to

(a)

to calculate the empirical formula of

A


thank you

hope it helpsss

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a sample of hydrogen gas (h2) is mixed with water vapor (h2o (g)). the make sure has a total pressure of 811 torr, and the water
Alborosie

Answer:

n=0.430molH_2

Explanation:

Hello!

In this case, considering the partial Dalton's law of partial pressures, we can notice that the total pressure equals the pressure of steam and the pressure of hydrogen, which can be determined as shown below:

p_T=p_H+p_w\\\\p_H=811torr-12torr=799torr*\frac{1atm}{760torr}\\\\p_H=1.05atm

Thus, by using the ideal gas law, we can compute the moles of hydrogen as shown below:

PV=nRT\\\\n= \frac{PV}{RT}=\frac{1.05atm*10.0L}{0.082\frac{atm*L}{mol*K}*298K}\\\\n=0.430molH_2

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Answer:

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A certain system absorbs 350 joules of heat and has 230 joules of work done on it what is the value of
marysya [2.9K]
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(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt 

(10.0 g) / (0.0480 mol) = 208.3 g/mol 

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A solution of ammonia and water contains 2.10×1025 water molecules and 7.10×1024 ammonia molecules. How many total hydrogen atom
Natali5045456 [20]

There are 6.33 × 10²⁵ hydrogen atoms in this solution in total.

<h3>Explanation</h3>
  • There are two hydrogen atoms in each water \text{H}_2\text{O} molecule.
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2.10 × 10²⁵ water molecules and 7.10 × 10²⁴ ammonia molecules will contain

2 \times 2.10 \times 10^{25} + 3 \times 7.10 \times 10^{24} = 6.33 \times 10^{25} hydrogen atoms in total.

8 0
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