Given: <span>10g^2+33g=9-2g^2
Group the q^2 terms first, then the q terms, and finally the constants:
12g^2 + 33q - 9 = 0. Make sure you agree with this, or otherwise fix it.
Tools for solving quadratic equations include the following and more:
graphing
quadratic formula
completing the square
I've graphed this simplified quadratic on my TI-83 calculator and see that -3 seems to be a root. Let's check it!
________________
-3 / 12 33 -9
-36 9
---------------------
12 -3 0 Since the remainder is zero, -3 is a root and (x+3) is a factor. The other factors are 3 and (4x -1)
Then 3(4g-1)(g+3) = 0, with the result that g = 1/4 and g = -3.
Please check these roots by subst. into the original equation.</span>
Answer:
I'm guessing 46 if its actually adding
Answer is 7.66"or 7.7"
cos40=x/10
calculate # 10*cos40
*note .. in your calculator don't forget to 'Degree'
[calculate]
10*cos40
answer is 7.7"
Answer:
Even tho it's not Christmas yet Merry Christmas
Step-by-step explanation:
The first and last one are the same the teo middle ones are the same. the two middle ones equal -20 and the last and first one equal 20. this is for the question above problem 3.2
