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Airida [17]
3 years ago
7

What is the solution to {2x +3y=11 and 3x+3y=18

Mathematics
1 answer:
ra1l [238]3 years ago
5 0

Answer:

The ordered pair that satisfies the equation is (7, -1)

Step-by-step explanation:

In order to find this, we can solve by subtracting. Start by stacking the two equations on top of one another and subtracting like terms.

3x + 3y = 18

(-) 2x + 3y = 11

--------------------

x = 7

Now that we have the value for x, we can plug in to either equation to find y.

2x + 3y = 11

2(7) + 3y = 11

14 + 3y = 11

3y = -3

y = -1

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Answer:

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Step-by-step explanation:

The equation of the parabola in the vertex form is:

y = a (x-h)² + k

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The parabola has a vertex at ( 0,4 )

So, h = 0 , k = 4

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The parabola passes through points ( 2,0 )

∴ 0 = a 2² + 4

∴ 4 a = -4  ⇒ a = -4/4 = -1

∴ y = -x² + 4

So, the equation of a parabola that has a vertex at ( 0,4 ) and passes through points ( 2,0 ) is <u>y = -x² + 4</u>

See the attached figure.

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Step-by-step explanation:

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xenn [34]

From trigonometry we know that:

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This can be rewritten in degrees as:

\theta=n(180^{\circ})+(-1)^n\alpha.............(Equation 1)

Now, in our case, \alpha=-230^{\circ}

Therefore, (Equation 1) can be written as:

\theta=n(180^{\circ})+(-1)^n(-230^{\circ})..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of \theta that match.

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Let n=-1, then:

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