<u>Answer:</u>
753.48 J
<u>Explanation:</u>
To increase the temperature of of m grams of water by n°C, you need to provide it with:
<em>heat = m x n x specific heat</em>
This will account for increasing the temperature of the first gram of water by n°C until you reach m grams of water.
q = mcΔT
where q = heat absorbed,
m = mass of sample,
c = specific heat of the substance; and
ΔT = the change in temperature
We know that the specific heat of water is 4.186 joule/gram °C so putting the values in the formula to get:
q = 9 x 4.186 x (20 - 0) = 753.48 J
