The balance chemical equation is follow,
2 I⁻ + SO₄²⁻ + 4 H⁺ → I₂ + SO₂ + 2 H₂O
According to this reaction, 2 moles of I⁻ reacts with 1 mole of SO₄²⁻ to produce 1 mole of I₂ and 1 mole of SO₂.
Result:
So with the formation of 1 mole of I₂, 1 mole of SO₂ is produced.
Answer: The mass of blue copper sulfate is 3.5 g
Explanation:
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The chemical equation for the heating of copper sulfate crystals is:
Let the mass of blue copper sulfate be 'x' grams
We are given:
Mass of copper sulfate powder = 2.1 grams
Mass of water = 1.4 grams
Total mass on reactant side = x
Total mass on product side = (2.1 + 1.4) g
So, by applying law of conservation of mass, we get:
Hence, the mass of blue copper sulfate is 3.5 grams
1. an alpha particle
gamma rays are formally massless, positrons and electrons (beta particles) have negligible mass, but alpha particles have about 4 amu of mass
