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Free_Kalibri [48]
2 years ago
6

Give the relation of energy (E) and frequency (v) as given by Planck. Calculate the frequency and energy of a photon of radiatio

n having wavelength 3000°A.
Pls answer correctly,need it urgently...
Chemistry
1 answer:
andrew-mc [135]2 years ago
4 0

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>1</u>

\\ \sf\longmapsto E=hv

  • E denotes to Energy
  • h denotes to planks constant
  • v denotes to frequency.

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>2</u>

  • Wavelength=3000Å

\boxed{\sf \lambda=\dfrac{c}{v}}

\\ \sf\longmapsto v=\dfrac{c}{\lambda}

\\ \sf\longmapsto v=\dfrac{3\times 10^8m/s}{3000\times 10^{-10}m}

\\ \sf\longmapsto v=0.001\times 10^{18}s^{-1}

\\ \sf\longmapsto v=1.0\times 10^{15}s^{-1}

Now

\\ \sf\longmapsto E=hv

\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 1.0\times 10^{15}s^{-1}

\\ \sf\longmapsto E=6.6\times 10^{-19}J

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What is the result of crystals boiling the impure product with too much solvent and then cooling on ice?
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Explanation:

It is known that when we tend to dilute an impure product with too much of solvent then it will lead to dissolution of the solute. As a result, the chances of formation of crystal reduces.

And, when we increase the temperature then there will occur increase in the number of collisions between the solute and solvent molecules.

Hence, solubility of the solute also increases with increase in temperature,  placing it on ice bath will further reduce the crystal formation, hence no crystal should be formed in the reaction.

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7 0
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5. A sample of benzene (C6H6), weighing 7.05 g underwent combustion in a bomb calorimeter by the following reaction:
Cloud [144]

Answer:

A sample of benzene (C6H6), weighing 7.05 g underwent combustion in a bomb calorimeter by the following reaction:

2 C6H6 (l) + 15 O2 (g) → 12 CO2 (g) + 6 H2O (l)

The heat given off was absorbed by 500 g of water and caused the temperature of the water and the calorimeter to rise from 25.00 to 53.13 oC. The heat capacity of water = 4.18 J/g/oC and the heat capacity of the calorimeter = 10.5 kJ/oC. (1) what is the ΔH of the reaction?

Explanation:

The heat energy released by the reaction = heat absorbed by calorimeter + heat absorbed by water

Heat absorbed by water = mass of water x specific heat capacity of water x change in temperature

Heat absorbed by water =  500 g x 4.18 J/g. oC x (53.13-25.00)oC

                                         = 58791.7 J

Heat absorbed by calorimeter = heat capacity of calorimeter x change in temperature

Heat absorbed by calorimeter = 10.5 x 10^3 J /oC  x (53.13-25.00)oC

                                                  =295365 J

Total heat energy absorbed = 58791.7 J + 295365 J  = 354156.7 J

Number of moles of benzene given is:

number of moles = goven mass of benzene /its molar mass

=7.05 g / 78.0 g/mol

=0.0903mol

Hence, the heat released by the reaction is:

= 354156.7 J / 0.0903 mol

=  3922.00 kJ/mol

Answer:

The heat released during the combustion of 7.05g of benzene is 3922.00kJ/mol.                                              

7 0
2 years ago
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