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3 years ago

10

Of the following elements aluminum, magnesium, aluminum, silicon, and sodium which has the smallest atomic radius? Explain your

answer.

1 answer:

viktelen [127]3 years ago

7 0

Answer:

Sodium

Explanation:

Radius grows as you go down and to the right on the ptable.

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Identify the homogeneous mixture among the following:

katen-ka-za [31]

Answer: air

Explanation:since individual components of air cannot be identified by merely looking at it, it is a homogeneous mixture.

4 0

1 year ago

The different forms of a gene for a given trait are called?

Olin [163]

Answer:

Allele

Explanation:

An allele is a variant form of a gene.some gene have a variety of different forms which are located at the same position or gentic locuson a chromosone. human are called diploid organisms becuase they jave two alleles at a each genitic locus with one allele inherited from each parent.

hope this helps you. pls mark me brainliest if you feel this answer is good.

thanks. if do have any question pls ask in the comment section.

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3 years ago

What is the pOH of a<br> 2.6 x 10-6 M H+ solution?

melomori [17]

Answer:

Approximately $8.41$ (assuming that the solution is at $\rm 25^\circ C$ , under which $K_{\rm w} = 10^{-14}$ .)

Explanation:

Let ${\rm [H^{+}]}$ and ${\rm [OH^{-}]}$ denote the concentration of $\rm H^{+}$ and $\rm OH^{-}$ respectively.

Let $K_{\rm w}$ denote the self-ionization constant of water. The exact value of $K_{\rm w}\!$ depends on the temperature of the solution. $K_{\rm w} =10^{-14}$ at $\rm 25^\circ C$ .

The product of ${\rm [H^{+}]}$ and ${\rm [OH^{-}]}$ in a solution (with $\rm M$ , or moles per liter, as the unit) is supposed to be equal to the $K_{\rm w}$ value of that solution at the corresponding temperature. In other words:

${\rm [H^{+}]} \cdot {\rm [OH^{-}]} = K_{\rm w}$ .

Rearrange to obtain an expression for ${[\rm OH^{-}]}$ :

$\begin{aligned}{\rm [OH^{-}]} &= \frac{K_{\rm w}}{[\rm H^{+}]}\end{aligned}$ .

Assume that the solution in this question is at $\rm 25^\circ C$ (for which $K_{\rm w} =10^{-14}$ .) For this solution:

$\begin{aligned}{\rm [OH^{-}]} &= \frac{K_{\rm w}}{[\rm H^{+}]} \\ &= \frac{10^{-14}}{2.6 \times 10^{-6}}\approx 3.85\times 10^{-9}\; \rm M\end{aligned}$ .

Hence, the $\rm pOH$ of this solution would be:

$\begin{aligned}\rm pOH &= -\log_{10}{\rm [OH^{-}]} \\&\approx -\log_{10} (3.85 \times 10^{-9}) \approx 8.41 \end{aligned}$ .

3 0

3 years ago

Which process is happening in the reaction that is shown

erastova [34]

I believe it’s B I apologize if it’s wrong

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3 years ago

Select all the correct answers.

frez [133]

Stir the water

Crush the salt

Heat the water

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3 years ago