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Darya [45]
3 years ago
15

An unstable nucleus loses the most mass if the nucleus emits

Chemistry
1 answer:
Sergio039 [100]3 years ago
6 0
1. an alpha particle

gamma rays are formally massless, positrons and electrons (beta particles) have negligible mass, but alpha particles have about 4 amu of mass
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Copper was the first metal to be produced from its ore because it is the easiest to smelt, that is, to refine by heating in the
Ganezh [65]

Answer:

57.48%

Explanation:

Calculate the mass of 1 mole of malachite:

MM Cu = 63.55

MM O = 16.00

MM H = 1.01

MM C = 12.01

(Cu_{2}(OH)_{2}CO_{3})

A mole of malachite has:

2 moles of Cu

5 moles of O

2 moles of H

1 mole of C

MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)

MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01

MW Malachite = 221.13

Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1

Now divide the mass of Cu by the mass of Malachite

%Cu = \frac{127.1}{221.13} =0.5748=57.48%

7 0
4 years ago
To begin legal proceedings against
Rudik [331]
What is the question? :)
8 0
3 years ago
Helpppppppppppppppppp
V125BC [204]

Answer:

sun wind water

Explanation:

3 0
3 years ago
Which of the solids investigated could be used to make a hand warmer? Describe soenbof the critical characteristics an ionic sol
Tatiana [17]

Answer:

Iron and vermiculite.

Explanation:

Iron and vermiculite are the solid substances used to make a hand warmer. Hand warmers contains iron, water, activated carbon, vermiculite, cellulose, and salt. The high melting, boiling points, hard and brittle are the characteristics of an ionic solid used in hand warmer. Iron is the ionic solid which is used in the hand warmer. Once iron exposed to air, the iron oxidizes and releases heat in the process.

5 0
3 years ago
The energy content of food is typically determined using a bomb calorimeter. Consider the combustion of a 0.22-g sample of butte
iren2701 [21]

Answer: The energy of combustion of butter is 31.5 kJ/g

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=C\times \Delta T

Q = Heat absorbed by calorimeter =?

C = heat capacity of calorimeter = 2.67kJ/^0C

Initial temperature of the calorimeter  = T_i = 23.5^0C

Final temperature of the calorimeter  = T_f  = 26.1^0C

Change in temperature ,\Delta T=T_f-T_i=(26.1-23.5)^0C=2.6^0C

Putting in the values, we get:

Q=2.67kJ/^0C\times 2.6^0C=6.94kJ

As heat absorbed by calorimeter is equal to heat released by combustion of butter

Q=q

Heat released by 0.22 g of butter = 6.94 kJ

Heat released by 1g of butter = \frac{6.94}{0.22}\times 1=31.5kJ

The energy of combustion of butter is 31.5 kJ/g

8 0
3 years ago
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