Question

If f:x = x +2 find the function g such that fgx = 20%2B%201" id="TexFormula1" title="2x {}^{2} + 3x + 1" alt="2x {}^{2} + 3x + 1" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

g(x) = 2x² + 3x - 1

Step-by-step explanation:

fg(x) = 2x² + 3x + 1

fg(x) = 2x² + 3x - 1 + 2

f(g(x)) = (2x² + 3x - 1) + 2

g(x) = 2x² + 3x - 1