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nadya68 [22]
3 years ago
14

An order calls for Hytone 1% cream, Lotrimin 1% cream, aa q.s. How many grams of Lotrimin cream would be needed to make a total

of 60 g of cream?
Chemistry
2 answers:
Ainat [17]3 years ago
7 0

The words aa q.s. is an abbreviation which is used in pharmacy. This is usually written by prescribers and then translated by pharmacists. The aa is derived from Latin which means “of each” while q.s. is also derived from Latin which means “a sufficient quantity”. This simply means that there is equal amount of Hytone 1% cream and Lotrimin 1% cream in the total cream formulation.

Since we are to make a total of 60 g of cream, therefore 50% of it would be Lotrimin cream.

Amount of Lotrimin cream needed = 0.5 (60 g)

<span>Amount of Lotrimin cream needed = 30 grams</span>

Novay_Z [31]3 years ago
7 0

Answer:

0.6~g~of~lotrimin

Explanation:

We have to keep in mind that the amount of lotrimin in the cream is 1%. Now the total of cream we want to make is 60 g. So, we have to ask us, what is 1% of 60 g? If we keep in mind that if we have 1% indicates that in 100 g of cream we have 1 g of lotrimin we can do the calculation:

60~g~of~cream\frac{1~g~of~lotrimin}{100~g~of~cream}

0.6~g~of~lotrimin

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marin [14]

Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

Explanation:

1. Calculate the moles of copper(II) hydroxide

\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}

2. Calculate the molecules of copper(II) hydroxide

\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

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